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anastassius [24]
2 years ago
14

Zara is serving a fresh pie.she starts by cutting the pie in half and then cuts each half into 4 equal pieces what fraction of t

he whole pie is each piece
Mathematics
1 answer:
gladu [14]2 years ago
5 0

Answer:

\boxed{\frac{1}{8}}

Step-by-step explanation:

You are starting with ½ pie. Then you cut it into four pieces.

You want to evaluate ½ ÷ 4

Step 1. Treat the integer as a fraction

\frac{1}{2}\div{\frac{4}{1}}

Step 2. Invert the divisor and change divide to multiply

\frac{1}{2}\times{\frac{1}{4}}

Step 3. Multiply numerators and denominators

\frac{1}{2}\times{\frac{1}{4}} = \mathbf{\frac{1}{8}}\\\\\text{Each piece is } \boxed{\mathbf{\frac{1}{8}}} \text{ of a whole pie.}

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
2 years ago
A shark swimming in the ocean sees a passing fish swimming by and accelerates at 2 m/s2 to a speed of 20 m/s to overtake it, doi
ratelena [41]

Answer:

The answer to your question is:      is = 14 m/s

Step-by-step explanation:

Data

acceleration = 2 m/s² = a

final speed = 20 m/s = sf

time = 3 seconds = t

initial speed = ? = is

Formula

sf = is + at

is = sf - at

Substitution

                        is = 20 - (2)(3)

                        is = 20 - 6

                        is = 14 m/s

5 0
2 years ago
The children from a football club are put into rows in the sports hall. When put into rows of 9 children, there are 2 children l
g100num [7]

We are told that the children from a football club are put into rows in the sports hall. When put into rows of 9 children there are 2 children left over. When put into rows of 12 children there are 2 children left over.

We will find least number of children in football club by finding LCM of 9 and 12.

Multiples of 9 are: 9, 18, 27, 36, 45, 54, 63,...

Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...

We can see that least common multiple of 9 and 12 is 36.

We are told that 2 children left over from putting them into 9 and 12 children per row. To find least number we will add 2 to 36.

9\cdot4+2=36+2=38

12\cdot3+2=36+2=38      

\text{Least number of children in football club}=36+2=38

Therefore, the least number of children in the football club is 38.

5 0
2 years ago
The cost of playing pool increases with the amount of time using the table. Identify the independent and dependent quantity in t
Marina CMI [18]
The cost is dependent on the time played because the cost and go up without the time going up
3 0
2 years ago
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If we collect experimental data on alcohol consumption from the same 100 individuals before and then after a course on the dange
Aleks [24]

Answer: D) randomized comparative design

Step-by-step explanation:

Randomized comparative design is an experiment which uses comparison of two or more treatments, also known as an experiment designed to show differences between two samples or populations which have being exposed to two different conditions or treatments are compared to each other. In the question above data collected before was compared to data gotten after the dangers of alcohol.

5 0
2 years ago
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