Given that function H(t) models the height of Pooja's plant (in centimeters) where t is the number of days after she bought it.
Now we have to find about which number type is more appropriate for the domain of h. That means what values can be taken by the variable "t".
Since t is number of days not the hours so t will not use decimal or fraction values. It can use integer values for the number of days.
Since time is counted after she bought the plant then number of days will be positive.
Hence answer for the type of domain can be positive integers or you can say integers greater than or equal to 0.
Answer:
t + 137 ≥ 625
Step-by-step explanation:
Shanelle already have in her possession the sum of $137 from babysitting. She requires at least $625 for a new tablet. t is the remaining amount she needs to get the new tablet.
She already has $137 and to get the tablet she needs at least $625 . This means she needs nothing less than or equal to $625 to get the tablet. Recall t is the remaining amount needed to add to what she has to be able to reach the least amount required to purchase a tablet. Therefore , the sum of t and the amount of money already in her possession should be equal to or greater than $625.
To get the new tablet,
t + 137 ≥ 625
Serious high school. This is one of the few differential equations I can solve.
The usual particular solution is
because
is its own derivative.
An independent solution is
which has a negative sign in the first derivative which turns back to positive in the second.
The arbitrary linear combination spans the solution space:

But we only are asked for the basis.
Answer:
Answer:
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
therefore
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction