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2 years ago

Write 3 different subtraction equations that equal 14.

Mathematics

2 answers:

borishaifa [10]2 years ago

7 0

Answer:

17-3=14

37-23=14

20-6=14

ratelena [41]2 years ago

5 0

Answer:

15-1=14

48-34=14

137-123=14

Step-by-step explanation:

To check work

14+1=15

14+34=48

14+123=137

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Minute Maid states that a bottle of juice contains 473 mL. Consumer groups are interested in determining if the bottles contain

olga2289 [7]

Answer:

Option C) The average contents of all bottles of juice in the population, which is 473 mL

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 473 mL

Sample mean, $\bar{x}$ = 472 mL

Sample size, n = 30

Sample standard deviation, σ = 0.2

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 473\text{ mL}\\H_A: \mu < 473\text{ mLinches}$

Representation of $\mu$

$\mu$ is the population parameter that represents the population mean.

Thus, for the given situation $\mu$ represents:

Option C) The average contents of all bottles of juice in the population, which is 473 mL

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2 years ago

Factor 125x9 + 64. (5x3 – 4)(25x6 + 20x3 + 16) (5x3 – 4)(25x3 + 20x3 + 16) (5x3 + 4)(25x6 – 20x3 + 16) (5x3 + 4)(25x3 – 20x3 + 1

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(5x^3 + 4)(25x^6 - 20x3 +16) remember factoring the cubes?

4 0

2 years ago

Read 2 more answers

A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids

NemiM [27]

Answer:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808$

And the answer for this case would be :

$s= 3.81$ after round the value

Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35$

Now we can find the sampel deviation with this formula:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808$

And the answer for this case would be :

$s= 3.81$ after round the value

6 0

2 years ago

In professional basketball games during 2009-2010, when Kobe Bryant of the Los Angeles Lakers shot a pair of free throws, 8 time

ziro4ka [17]

Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

__________________________________________________

First shot Made Second shot missed Total

__________________________________________________

Made 152 33 185

Missed 37 8 45

__________________________________________________

Total 189 41 230

2) Calculations and test

We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

Null hypothesis: Independence between two successive free throws

Alternative hypothesis: No Independence between two successive free throws

_____________________________________________________

First shot Made Second shot missed

_____________________________________________________

Made 189(185)/230=152.0217 41(185)/230=32.9783

Missed 189(45)/230=36.9783 41(45)/230=8.0217

_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

3) Calculate the chi square statistic

The statistic for this case is given by:

$\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}$

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

$\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881$

Now with the calculated value we can find the degrees of freedom

$df=(r-1)(c-1)=(2-1)(2-1)=1$ on this case r means the number of rows and c the number of columns.

Now we can calculate the p value

$p_v =P(\chi^2 >0.00008881)=0.9925$

On this case the pvalue is a very large value and that indicates that we can fail to reject the null hypothesis of independence. So is plausible that the successive throws are independent.

5 0

2 years ago

In a survey of 2,300 people who owned a certain type of car, 1,610 said they would buy that type of car again. What percent of t

trapecia [35]

Answer:

In a survey of 2,300 people who owned a certain type of car, 1,610 said they would buy that type of car again. What percent of the people surveyed were satisfied with the car?

1610/2300x100=

70%

Step-by-step explanation:

total number of people for the survey= 2300

those that wanted to buy the car= 1610

percentage= 1610/2300x 100=0.7x 100

percentage= 70%

3 0

2 years ago