Answer:
See below
Step-by-step explanation:
<u>Given points:</u>
- S(-3,6),T(0,7),U(1,4),and V(-5,2)
<u>Translation rule: </u>
<u>New coordinates by applying the rule:</u>
- S'(4, -3), T'(7, -2), U'(8, -5), V'(2, -7)
See attached for the graph
The blue trapezoid is STUV and the red one is S'T'U'V'

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.
Answer:
1 . Closure
2. Distributive
3. Closure
Step-by-step explanation:
Here, we want to know the type of property exhibited or displayed by each of the equations in the question.
Equation 1 displays the closure property.
What this means that if we make an addition operation either way, we would get same answer. So we say that addition is closed for that equation.
Equation 3 exhibits closure property as well. If we go either way on the addition operation for that equation, we are bound to get the same answer.
Equation 2 exhibits the distributive property.
Each term in the bracket is multiplied by the subtraction symbol before we proceeded to complete the arithmetic operations
$137.60 (gross pay)
$10.53 (FICA)
$13.18 (Federal Tax)
$9.81 (State Tax)
---------------------------------
$103.78 (Net Pay)
$77.84 (Deposit)
---------------------------------
$25.94 (To You)
$38.92 (To Savings)
Answer:
It is proved that
exixts at (0,0) but not differentiable there.
Step-by-step explanation:
Given function is,

- To show exixtance of
we take,
exists.
And,
exists.
- To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,
where m is a variable.
which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).