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lions [1.4K]
1 year ago
9

Points E, F, and D are located on circle C. Circle C is shown. Line segments E C and D F are radii. Lines are drawn from points

E and D to point F to form chords E F and D F. Arc E D is 68 degrees. The measure of arc ED is 68°. What is the measure of angle EFD? 34° 68° 112° 132°

Mathematics
2 answers:
elena55 [62]1 year ago
7 0

Answer:

Option (1). 34°

Step-by-step explanation:

From the figure attached, CE and CD are the radii of the circle C.

Central angle CED formed by the intercepted arc DE = 68°

Since measure of an arc = central angle formed by the intercepted arc

Therefore, m∠CED = 68°

Since m∠EFD = \frac{1}{2}(m\angle ECD) [Central angle of an intercepted arc measure  the double of the inscribed angle by the same arc]

Therefore, m∠EFD = \frac{1}{2}(68)

                               = 34°

Therefore, Option (1) 34° will be the answer.

marusya05 [52]1 year ago
7 0

Answer:

34 (100% Correct)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 0
2 years ago
According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1
JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means p=0.10 and q=1-0.10=0.90.

If 1100 Americans are sampled, then the sample size is n=1100 .

The mean of the distribution is \mu=np.

This means \mu=1100\times 0.10=110

The standard deviation is \sigma=\sqrt{npq}

We substitute the values to get:

\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)

We now convert to Z-scores to get:

P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)

We convert to z-scores:

P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48

From the normal distribution, P(z>164.5)=0

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We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\le88)=P(X\:

We convert to z-scores:

P(X\:

From the normal distribution, P(z>\:-2.16)=0.0154

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3 0
2 years ago
Round to the nearest ten thousand 905154
kolbaska11 [484]
You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:

9<em><u>0</u></em>5,154

    To round 905,154 to the nearest ten-thousands place...

    The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.

    Since the 5 is greater than or equal to 5, we'll round our number up by

        Adding 1 to the 0 in the ten-thousands place, making it a 1.

    and by changing all digits to the right of this new 1 into zeros.

The result is: 910,000.

So, 905,154 rounded to the ten-thousands place is 910,000.

5 0
2 years ago
To order tickets online to a hockey game, there is a processing fee plus the cost per ticket. The cost for 5 tickets is $174.45.
xeze [42]
Wouldn’t the total for 13 tickets be $446.40 ? We already know the cost for 5 and 8 just add it up .... js
3 0
1 year ago
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Serhud [2]

Answer:

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Step-by-step explanation:

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I = Prt

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In our problem, we have that:

He borrowed $4,400, so P = 4,400

At 4.75% yearly. We measure the time in days, so we have to divide this value by 365. So r = \frac{0.0475}{365}.

From December 26, 2019 to February 21, 2021, there are 422 days, so t = 422.

I = Prt

I = 4,400\frac{0.0475}{365} 422

I = 253.09

He paid $253.09 in interest.

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1 year ago
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