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bixtya [17]
1 year ago
9

In a science-fiction story, a spaceship travels 3 times faster each minute than it traveled during the minute before. If the shi

p travels at 3 km/hr during its first minute of flight, which expression shows the ship's speed in kilometers per hour during the 15th minute?
Mathematics
1 answer:
JulijaS [17]1 year ago
6 0

The expression is:

speed(minutes)=3\frac{km}{h} ^{minutes} \\\\speed(15minutes)=(3^{15})\frac{km}{4} =14348907\frac{km}{g}

Why?

From the statement we know that the spaceship travels 3 times faster each minute that it traveled during the minute before, it can be expressed using an exponential function, its base will be the starting speed (during the first minute).

The expression will be:

speed(minutes)=(3^{minutes})\frac{km}{h} \\\\speed(15minutes)=(3^{15})\frac{km}{h}=14348907\frac{km}{h}

Have a nice day!

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(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).
Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = \frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use <u>product rule</u>,i.e., \frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}

this will give <em>k'(x)=f'(x)g(x) + f(x)g'(x)</em>

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)} ]. Since m(x) has a function g(x) in the denominator so we need to use <u>division rule</u> to differentiate m(x). Division rule is as follows : \frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}

this will give <em>m'(x) = \frac{1}{2}\times\frac{f'(x)g(x) - f(x)g'(x)}{g^{2}(x) }</em>

on substituting the value x=5, we will get the value of m'(5).

{for expressing the value in terms of numbers first we need to know the value of f(5), g(5), f'(5) and g'(5) in terms of numbers}

{NOTE : in m(x), g(x) ≠ 0 for all x in domain to make m(x) defined and even m'(x) }

{ NOTE : \frac{\mathrm{d} f(x)}{\mathrm{d} x}=f'(x) }

4 0
1 year ago
You find a certain stock that had returns of 8 percent, −3 percent, 12 percent, and 17 percent for four of the last five years.
Tatiana [17]

Answer:

Standard deviation = 8.27 percent

Step-by-step explanation:

Average = (Σx)/N

The average is the sum of variables divided by the number of variables.

x = each variable

N = number of variables = 5

Let the unknown percent be y

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The standard deviation is the square root of variance. And variance is an average of the squared deviations from the mean.

Mathematically,

Standard deviation = σ = √[Σ(x - xbar)²/N]

x = each variable

xbar = mean = 6 percent

N = number of variables

σ = √[{(8 - 6)² + (-3 - 6)² + (12 - 6)² + (17 - 6)² + (-4 - 6)²}]/(5)]

σ = √[[(2)² + (-9)² + (6)² + (11)² + (-10)²]/(5)]

σ = √[(4 + 81 + 36 + 121 + 100)/(5)] = √(342/5) = 8.27 percent.

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Answer:

she can select 10 different ways

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There would be fewer meter. Since 1 m=100 cm.
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