To solve this problem, let us first find for the binary
equivalents of the numbers. They are:
Decimal --> Binary
+ 29 --> 00011101
+ 49 --> 00110001
- 29 --> 11100011
- 49 --> 11001111
Now we apply the normal binary arithmetic to these converted
numbers:
(+ 29) + (- 49) ---> 00011101 + 11001111 =
11101100 ---> - 20 (TRUE)
(- 29) + (+ 49) ---> 11100011 + 00110001 = 00010100
---> + 20 (TRUE)
(- 29) + (- 49) ---> 11100011 + 11001111 = 10110010
---> - 78 (TRUE)
Answer:
3 hours of tv per day
Step-by-step explanation:
there are 7 days in a week
21/7 = 3
Answer:
166 2/13 deg
Step-by-step explanation:
The sum of the measures of the interior angles of a convex polygon of n sides is 180(n - 2).
A hexagon has 6 sides, so n = 6.
sum of measures of angles = 180(n - 2) = 180(6 - 2) = 180(4) = 720
4x + 5x + 6x + 7x + 8x + 9x = 720
39x = 720
x = 720/39
x = 240/13
The largest angle has measure 9x.
9x = 9 * 240/13 = 2160/13
2160/13 = 166 2/13
Answer: 166 2/13 deg
Answer:
Hello some parts of your question is missing below is the missing part
c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces
Answer: A) 0.0099
B) 0.6796
C) 0.13956
Step-by-step explanation:
weight of Navel oranges evenly distributed
mean ( u ) = 8 ounces
std ( б )= 1.5
navel oranges = X
A ) percentage of oranges weighing more than 11.5 ounces
P( x > 11.5 ) = 
= P ( Z > 2.33 ) = 0.0099
= 0.9%
B) percentage of oranges weighing less than 8.7 ounces
P( x < 8.7 ) = 
= P ( Z < 0.4667 ) = 0.6796
= 67.96%
C ) probability of orange selected weighing between 6.2 and 7 ounces?
P ( 6.2 < X < 7 ) = 
= P ( -1.2 < Z < -0.66 )
= Ф ( -0.66 ) - Ф(-1.2) = 0.13956