Answer: - 2.5
Step-by-step explanation:
Using the attached number line has reference, the distance between each integer on the number line attached is 1, and the numbers are ordered in ascending order from - 10 to + 10. The point R exists in between the point marked - 2 and - 3 respectively. This shows that that point R is a number between the two integers, a number greater than - 3 but less than - 2.
From the picture attached the blue dot sits directly at the midpoint between - 3 and - 2. Hence the position can be a obtained by averaging the two integers.
(-3 + - 2) / 2 = - 5/2 = - 2.5
5+ 4e = -7 is the correct answer.
Answer:
m
-5.6
Step-by-step explanation:
-5m-5
23
-5m
28
m
-5.6
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.



Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer:
909.8 millibars.
Step-by-step explanation:
The mean sustained velocity, v be determined by the equation:
, where p is the air pressure, in millibars, at the center of the hurricane.
Given that: v=64 meters per second, we are to <u>find the value of p.</u>
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The approximate air pressure at the center of a hurricane when the mean sustained wind velocity is 64 meters per second is 909.8 millibars.