A bicyclist travels at a constant speed of 12 miles per hour for a total of 45 minutes.
We know the formula , Distance = speed * time
Speed is constant and it is 12. So it is linear
The function becomes d = 12t, x is the t is the time and d is the distance
At the starting point, t=0 and distance d=0
End point , t=45 min = 0.75 hours and distance = 12 * 0.75 = 9
So domain (t) is {}
Range (d) is {}
Given:
On the first day, she drove 650 miles in 10 hours.
On the second day, she got a later start and drove 540 miles in 8 hours.
To find:
Difference between average speed of second day and first day.
Solution:
We know that,
On the first day, she drove 650 miles in 10 hours. So, the average speed is
So, the average speed on first day is 65 miles per hour.
On the second day, she got a later start and drove 540 miles in 8 hours.
So, the average speed on second day is 67.5 miles per hour.
Difference between average speed is
Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.