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Ilya [14]
2 years ago
14

PlEASE HELP WITH THIS QUESTION Lisa bought 5 CDs from a store. The price of each CD was the same. After she bought the CDs, her

account balance showed a change of −$64.95. What would have been the change to Lisa's account balance had she only bought 1 CD from the store?
−$59.95
−$12.99
$12.99
$59.95
Mathematics
1 answer:
slava [35]2 years ago
8 0

Answer:

-12.99

Step-by-step explanation:

-64.95 / 5 = -12.99

The change would be -12.99

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Cindy owns a rectangular lot that is 18 yards long and 45 feet wide. She is going to cover the lot with square pieces of sod. If
QveST [7]
It would be 9720 because 18 times 45 would be 810 then times that by 12 would equal 9720.
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2 years ago
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The average MCAT score follows a Normal distribution, with a mean of μ = 508 and a standard deviation of σ = 8. What is the prob
dusya [7]

Subtract the mean from the high score and divide by the standard deviation:

510 - 508 = 2

2/8 = 0.25

Using the Z tabe find the z value for 0.25 = 0.5987

Now subtract that value from 1:

1 - 0.5987 = 0.4013

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Jenna offers regular haircuts for $25 and haircuts plus coloring for $42.This weekend had a total of 24 clients and Jenna earned
shepuryov [24]
<u><em>Answer:</em></u>
Jenna did 16 regular haircuts
Jenna did 8 haircuts with coloring

<u><em>Explanation:</em></u>
Assume that the number of regular haircuts is x and the number of haircuts plus coloring is y

<u>We are given that:</u>
<u>1- Jenna did a total of 24 clients, this means that:</u>
x + y = 24
This can be rewritten as:
x = 24 - y ...............> equation I

<u>2- regular haircuts cost $25, haircuts plus coloring cost $42 and she earned a total of $736. This means that:</u>
25x + 42y = 736 ..........> equation II

<u>Substitute with equation I in equation II and solve for y as follows:</u>
25x + 42y = 736
25(24-y) + 42y = 736
600 - 25y + 42y = 736
17y = 136
y = 8

<u>Substitute with y in equation I to get x as follows:</u>
x = 24 - y
x = 24 - 8
x = 16

<u>Based on the above:</u>
Jenna did 16 regular haircuts
Jenna did 8 haircuts with coloring

Hope this helps :)
5 0
2 years ago
The yearly cost in dollars, y, at a video game arcade based on total game tokens purchased, x, is y = y equals StartFraction 1 O
klio [65]

Answer:

The members slope is flatter by half compared to the non-members slope. The graphs intersect at 600 tokens and $120. Until that point the cost for non-members is less than the cost for members. After 600 tokens the cost for members is less than the cost for non-members.

Step-by-step explanation:

I hope I have your equations correct:

Member:

y = 1/10x + 60

Non-Member:

y = 1/5x

6 0
2 years ago
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The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
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