Question

Javier read a report that said the probability that a randomly selected American is left-handed is 14\%14%14, percent. He was curious how many left-handed students to expect in a class of 303030 students. He simulated 100100100 classes of 303030 students where each student selected had a 0.140.140, point, 14 probability of being left-handed. Javier counted how many left-handed students were in each simulated class. Here are his results: Use his results to estimate the probability that there are 777 or more left-handed students in a class of 303030 students. Give your answer as either a fraction or a decimal. P(7\text{ or more left-handed})\approxP(7 or more left-handed)≈P, left parenthesis, 7, start text, space, o, r, space, m, o, r, e, space, l, e, f, t, negative, h, a, n, d, e, d, end text, right parenthesis, approximately equals

Answer 1

Answer:

5/100

Step-by-step explanation:

Answer 2

Answer:

= 0.1165

Step-by-step explanation:

In statistics, binomial distribution table  are ones in which one of two outcomes may result. Given the number of trials in an experiment ''n'', you can use these binomial distribution tables to look up the probability of a certain number of successes in the whole experiment.

P=14% = 0.14, n=30

Here we can use binomial distribution use binomial cumulative tables

Then P(More than 7) = P(x>7)

= 1 - P(x < 7)

= 1 - P(x ≤ 6)

= 1 - 0.8835

= 0.1165