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Goryan [66]
2 years ago
7

If you apply the changes below to the quadratic parent function, f(x) = x2, what is the equation of the new function? Shift 3 un

its right. Vertically stretch by a factor of 4. Reflect over the x-axis. A. g(x) = (–4x – 3)2 B. g(x) = –4(x – 3)2 C. g(x) = 4x2 + 3 D. g(x) = –4(x + 3)2
Mathematics
1 answer:
Alex17521 [72]2 years ago
8 0
To apply the changes to the equation of a vertical stretch of 4 and a translation of 3 units to the right, as well as the correct answer would be choice B.

The reason for this is when you apply a vertical stretch, because it changes the y-values (which causes it to vertically stretch or appear skinnier when graphed), you would multiply 4 to f(x) which would look like 4x^2.

Then, since you have a reflection over the x-axis, you must multiply a -1 to f(x) to reflect it over the x-axis which would result in -4x^2.

Finally, it also asks to shift the graph right 3 which by moving it right, you change the x values meaning you will perform f(x-3) to achieve this (subtract the value from x when you move right, and add the value to x when you move left).

This therefore results in your answer, the new graph would be
g(x)= -4(x-3)^2 or choice B.
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Answer: 13% increase?

Step-by-step explanation: 19-6=13 which means it would be 1.13 the original amount?

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What is 2 divided 1 6/7 ? Please answer
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If you would like to divide 2 by 1 6/7, you can do this using the following steps:

1 6/7 = 13/7

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The correct result would be 1 1/13.
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2 years ago
What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min
Ilya [14]

Answer:

Value of expression in single logarithm is \log_3\left(2z^2\right).

Step-by-step explanation:

Given expression is,

2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)

Therefore,

2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)

Applying power rule of logarithmic,

a\log_c\left(b\right)=\log_c\left(b^a\right)

Therefore,

\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)

\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)

Applying quotient rule of logarithmic,

\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)

Therefore,

\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)

Simplifying,

\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)

\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)

\log_3\left(2z^2\right)

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6 0
2 years ago
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A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange.Let B = t
pentagon [3]

Answer:

P(R\ and\ B) = 0.0256

Step-by-step explanation:

Given

Red = 22

Yellow = 38

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Blue = 26

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Required

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From the question, we understand that the red jelly bean was not replaced. This means that the number of jelly beans reduced by 1 after the picking of the red jelly bean

So, we have:

P(R\ and\ B) = P(R)\ and\ P(B)

This is then solved further as:

P(R\ and\ B) = P(R)\ *\ P(B)

P(R\ and\ B) = \frac{n(R)}{Total}\ *\frac{n(B)}{Total - 1}

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The equation becomes:

P(R\ and\ B) = \frac{22}{150}\ *\frac{26}{150- 1}

P(R\ and\ B) = \frac{22}{150}\ *\frac{26}{149}

P(R\ and\ B) = \frac{22*26}{150*149}

P(R\ and\ B) = \frac{572}{22350}

P(R\ and\ B) = 0.02559284116

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