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AleksAgata [21]
2 years ago
10

of the box of pens in a box, 2/7 of them are red. of the remaining pens 1/6 of them are blue and the ret are black. there are 28

0 more black pens than blue pens. how many red pens are there.
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
3 0

Answer:

The red pens are 168.

Step-by-step explanation:

Given:

In a box of pens, 2/7 of them are red. of the remaining pens 1/6 of them are blue and the rest are black. there are 280 more black pens than blue pens.

Now, to find the red pens in the box.

Let the total pens be x.

Red pens be \frac{2}{7} of x =\frac{2x}{7}

Remaining pens = x-\frac{2x}{7} =\frac{5x}{7}

So, blue pens = \frac{1}{6} of \frac{5x}{7} =\frac{5x}{42}

Now, black pens = x-(blue +red)

Black pens = x-\frac{2x}{7}+\frac{5x}{42}

According to question:

Black pens = Blue pens + 280

x-\frac{2x}{7}+\frac{5x}{42}=\frac{5x}{42}+280

x-\frac{17x}{42}=\frac{5x}{42}+280

x-\frac{22x}{42}=280

20\frac{x}{42}=280

x=\frac{280\times 42}{20}

<em>On solving we get:</em>

x=588

So, red pens = \frac{2x}{7}=\frac{2\times 588}{7}

                      =168.

Therefore, the red pens are 168.

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MrRissso [65]
To answer the question above, we are simply to subtract the length of the gold ribbon which is 2 4/6 ft from the length of the silver ribbon, 5 2/6 feet. Mathematically,
                                5 2/6 feet - 2 4/6 feet = 8/3 feet 
Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon. 
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Alicia buys a 5 pound bag of rocks for a fish tank. She uses 1 1/8 pounds of small fish bowl. How much is left?
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5-1 and 1/8=
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Sophie could $330 in a savings account at a simple interest rate of 4% per year. Avi put $290 in a savings account at a simple i
worty [1.4K]
Sophie would’ve earned more
She would’ve earned $37 more

Calculations:
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$330(1+4%*2)
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Avi:
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PI-3.
Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

x=2q_1+1

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

x=3q_2+1

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

x=7q_6

This means x-1 is divisible by 2, 3, 4, 5 and 6 without remainder, so

x-1=2\cdot 3\cdot 2\cdot 5n=60n

Hence,

x=60n+1, \ n\in N

The smallest amount of money they could have raised is $301, because

x=60\cdot 5+1=301 is divisible by 7.

Now, the number x=60n+1 should be divisible by 7 and must be greater than 500.

So,

60n+1>500\\ \\60n>499\\ \\n>8

When n = 9,

x=60\cdot 9+1=541 is not divisible by 7.

When n = 10,

x=60\cdot 10+1=601 is not divisible by 7.

When n = 11,

x=60\cdot 11+1=661 is not divisible by 7.

When n = 12,

x=60\cdot 12+1=721 is divisible by 7.

B. The least amount of money they could have raised is $721

7 0
1 year ago
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Use the table and the data provided to analyze the following data. During gym class, the pulse rate was recorded for 19 students
nexus9112 [7]

Answer:

Part A

Please see attached the required stem and leaf plot

For the stem and leaf plot, the nonsplit system is used because of clarity for analysis

Part B:

From the shape of the stem and leaf plot we have that there is an average increase of pulse rate of 20 pulses in all the 19 students after the exercise

The shape of the plot is relatively the same for the before and after exercise save for the decrease in the third to the last row by one and the increase in the second to the last roe by one student

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Step-by-step explanation:

The given data are;

67{}                                    87

67{}                                    88

67 {}                                   89

68 {}                                   89

71 {}                                    91

72                                   93

72                                   93

75                                   95

77                                   96

77                                   97

79                                   98

81                                    98

85                                   101

87                                   105

87                                   105

91                                    119

97                                   125

103                                  125

121                                  147

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