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Lelu [443]
1 year ago
9

A toy airplane climbs 30 vertical feet while traveling 50 feet horizontally. A toy helicopter climbs 20 feet while traveling 40

feet horizontally. Assuming a steady rate of change, which toy traveled at a great slope?
Mathematics
1 answer:
Amiraneli [1.4K]1 year ago
7 0

Answer:

k

Step-by-step explanation:

u

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A rectangular field is enclosed by 360 feet of fencing. What is the length, in feet, of the field if it’s length is 6 feet more
Orlov [11]

Answer:

The Field's length is 93ft

Step-by-step explanation:

P=2L+2w

360=2(w+6)+2w

360=2w+12+2w

360=4w+12

348=4w

348/4=w

87=w

L=w+6

L=87+6

L=93

7 0
2 years ago
A juice drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of drink on an average. Any overfill
ozzi

Answer:

d. The average is equal to 12 ounces.

Step-by-step explanation:

In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:

H_0:\mu=12\\H_a:\mu\neq 12

The correct alternative is d. The average is equal to 12 ounces.

5 0
2 years ago
A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t
maksim [4K]

Answer:

Boat traveled 553.24 feet towards the lighthouse.

Step-by-step explanation:

In the figure attached AB is the light house of height 200 feet.

Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'

so 1' = \frac{1}{60} degree

so angle of elevation at point C = 14 + \frac{52}{60}

So angle of elevation from C = (14 + 0.87) = 14.87°

Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + \frac{10}{60} = 45.17°

Now we have to calculate the distance CD, traveled by the boat.

In ΔABC

tan14.87 = \frac{200}{BC}

0.2655 =  \frac{200}{BC}

BC = \frac{200}{0.26552}

BC = 753.239 feet

Similarly in ΔABD

tan45.17 = \frac{200}{BD}

1 = \frac{200}{BD}

BD = 200 feet

So distance CD = BC - BD

CD = 753.239 - 200

     = 553.24 feet

Therefore, Boat traveled 553.24 feet towards the lighthouse.

7 0
2 years ago
Read 2 more answers
Find the distance between the points p1 (2,-5) And p2 (-4,3)
jekas [21]
(6,8) i think that is the correct answer. 
4 0
2 years ago
Read 2 more answers
Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot.
stiks02 [169]

Answer:

Nolan correctly identified the square  numbers before and after 18.

The square roots of them are 4 and 5.

Clearly, square root of 18 should lie between 4 and 5 only.

He, then carefully squared 4.1, 4.2, 4.3 etc. and identified that 4.3 squared is nearer to 18.

Since, Nolan is finding estimated square root, his steps are cool and he didn't make any error.

4 0
1 year ago
Read 2 more answers
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