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arsen [322]
2 years ago
6

–9x + 10y = –9 whats that in slope intercept form

Mathematics
2 answers:
ziro4ka [17]2 years ago
6 0

Answer:

Slope intercept form of the line is y = \frac{9}{10}x-\frac{9}{10}

Step-by-step explanation:

Equation of a line has been given as -9x + 10y = -9

It's a standard form of the equation and we have to convert it into slope intercept form.

Slope intercept form of the line is in the form of y = mx + c

Where m = slope of the line

c = y-intercept of the line

-9x + 10y = -9

10y = 9x - 9

y = \frac{1}{10}(9x-9)

y = \frac{9}{10}x-\frac{9}{10}

Therefore, slope intercept form of the line will be y = \frac{9}{10}x-\frac{9}{10}

kirill115 [55]2 years ago
4 0
Slope intercept form is y = mx + b

so make the equation look like that. 

-9x + 10y = -9 ... add 9x on both sides 
10y = -9 + 9x 
10y = 9x - 9 
<span>
y = (9/10)x - (9/10)


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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2 years ago
Anna gets paid $8.75/hour working as a barista at Coffee Break. Her boss pays her $9.00/hour for creating the weekly advertiseme
vladimir1956 [14]

Answer:

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Step-by-step explanation:

just add 8.75 to 9.00 then multiply it by 25

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7 0
2 years ago
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

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Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

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{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

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\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

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Answer:

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