LK is tangent to circle J at point K. What is the length of the radius? 6/25 85/12 121/36 157/12
2 answers:
Answer:
The answer is indeed, 85/12 ; B
Using the Pythagorean theorem, you can use FOIL to solve for the hypotenuse then subtract the radius from the entire hypotenuse to find R. Since all radii are congruent.
Simplify the rest. We also know that (6+r)^2 is the hypotenuse since angle JKL is a right angle as it is perpendicular to the center and is a tangent.
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Answer:
-- Swing set
-- Slide
--- Pathway
Step-by-step explanation:
Missing part of the question:
Fill in the table above to show the area of each section (see attachment for table)
The area of each section is calculated as:
For the Swing set
For the Slide
For the Pathway
The total area is:
<h2>Answer:</h2>
- The optimal solution to the given linear programming problem exist at (100,50)
- and the optimal solution is: 5A+5B= 750
We are given a system of linear programming problem as follows:
Max 5A + 5B
s.t. A ≤ 100---------------(1)
B ≤ 80-------------(2)
2A+4B ≤400-------------(3)
which is given by:
A+2B ≤ 200
and A,B≥0
This means that the solution to this LPP will lie in the first quadrant.
( Since, both the variables A and B are greater than or equal to zero)
Now, we consider that A is represented by the x axis and B by y-axis.
We know that the optimal solution always exist at the boundary point.
Hence, by plotting these inequalities in the graph we get the boundary points as:
(0,0) , (0,80) , (100,0) , (100,50) and (40,80)
Now, we will check at which boundary point the optimal function is maximized .
Point Value of optimal function( 5A+5B)
(0,0) 0
(0,80) 400
(100,0) 500
(100,50) 750
(40,80) 600
The maximum value is obtained at (100,50).
and the value of the optimal solution is: 750