LK is tangent to circle J at point K. What is the length of the radius? 6/25 85/12 121/36 157/12
2 answers:
Answer:
The answer is indeed, 85/12 ; B
Using the Pythagorean theorem, you can use FOIL to solve for the hypotenuse then subtract the radius from the entire hypotenuse to find R. Since all radii are congruent.
Simplify the rest. We also know that (6+r)^2 is the hypotenuse since angle JKL is a right angle as it is perpendicular to the center and is a tangent.
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Answer:
B) 28.53 unit²
Step-by-step explanation:
The diagonal AD divides the quadrilateral in two triangles:
- Triangle ABD
- Triangle ACD
Area of Quadrilateral will be equal to the sum of Areas of both triangles.
i.e.
Area of ABCD = Area of ABD + Area of ACD
Area of Triangle ABD:
Area of a triangle is given as:
Base = AB = 2.89
Height = AD = 8.6
Using these values, we get:
Thus, Area of Triangle ABD is 12.43 square units
Area of Triangle ACD:
Base = AC = 4.3
Height = CD = 7.58
Using the values in formula of area, we get:
Thus, Area of Triangle ACD is 16.30 square units
Area of Quadrilateral ABCD:
The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²
None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²