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katen-ka-za [31]
2 years ago
5

Lynn is making custom bricks. She combines 39 pounds of water and 48 pounds of brick dust in a mixing bucket. She spills 13 poun

ds of the mixture while stirring the contents. The mixture is then poured into small dirt holes to make bricks. Each brick requires 7 pounds of mixture, and the leftover mixture is washed out of the mixing bucket.
What is the greatest number of bricks Lynn can make?
bricks
How many pounds of mixture will be washed out of the bucket if Lynn makes the greatest number of bricks?
Mathematics
1 answer:
ehidna [41]2 years ago
5 0

Lynn mixes 39 pounds of water with 48 pounds of brick dust, so the mixture has a total weight of 39 + 48 = 87 pounds.

13 pounds are spilled during mixing, so she's left with 87 - 13 = 74 pounds to turn into bricks.

7 pounds are needed for 1 brick, so she can make 10 bricks because 7 • 10 = 70 and 7 • 11 = 77, and 70 < 74 < 77.

If she uses the mixture to make 10 bricks, she uses up 70 pounds of it, which leaves 4 pounds to be washed out.

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Answer:

<h2>5,936.76 feet/day</h2>

Step-by-step explanation:

Formula to use to get the speed is expressed as speed = Distance/Time

Given parameters

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Time = 7.5weeks

Since we are to express the answer in feet per day, we will convert the distance to feet and time to days.

For the distance:

Given the conversion

1 km = 3280.84 feet

95km = (95*3280.84)feet

95km = 311,679.8 feet

For the time:

If 1 week = 7 days

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7.5weeks = 52.5 days

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3 0
2 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
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              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















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