For this case we have a function of the form:
y = f (x)
Where,
x: independent variable
y: dependent variable
To answer the question, we must see in the table the values of the independent variable x, for which the values of the dependent variable f (x) are negative.
We have then that the interval that fulfills this condition is from minus infinity to minus 4 without including the 4.
Thus,
(–∞, –4)
Answer:
The entire interval over which the function, f(x), is negative is:
D) (–∞, –4)
Answer:
2/7 or 0.2857
Step-by-step explanation:
The expected time before the first bulb burns out (two bulbs working) is given by the inverse of the probability that a bulb will go out each day:

The expected time before the second bulb burns out (one bulb working), after the first bulb goes out, is given by the inverse of the probability that the second bulb will go out each day:

Therefore, the long-run fraction of time that there is exactly one bulb working is:

There is exactly one bulb working 2/7 or 0.2857 of the time.
Answer:
Option (D)
Step-by-step explanation:
Given polynomial is,
2x³ - 3x² - 3x + 2
If (x - 2) is the factor of the given polynomial,
By synthetic division we can get the other factor.
2 | 2 -3 -3 2
<u> 4 2 -2 </u>
2 1 -1 0
Therefore, other factor of the given polynomial is (2x² + x - 1)
Now (2x² + x - 1) = 2x² + 2x - x - 1
= 2x(x + 1) -1(x + 1)
= (2x - 1)(x + 1)
Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)
Option (D) will be the answer.
Answer:
There are 20 vegetable plants in garden.
Step-by-step explanation:
We are given the following in the question:
Percentage of flowers = 60%
Percentage of vegetable = 40%
Number of plants in garden = 50
Number of vegetables in garden =

Number of flowers in garden =

Thus, there are 20 vegetable plants in garden.
We have to calculate the difference of the given polynomials, we follows as:

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.
=
Combining all the like terms, we get as
=
=
Option A is the correct answer.