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Ierofanga [76]
2 years ago
5

Write a multiplication equation and a division equation for each statement or diagram. Eight $5 bills are worth $40. There are 9

thirds in 3 ones. A tape diagram of 5 equal parts. Each part is labeled one fifth. Above the bar is a bracket, labeled 1, that spans the entire length of the bar.
Mathematics
2 answers:
OLga [1]2 years ago
5 0

Answer:

Eight $5 bills are worth $40.  5x8=40                40/5=8

There are 9 thirds in 3 ones. 3x3=9                    9/3=3

A tape diagram of 5 equal parts. Each part is labeled one fifth. Above the bar is a bracket, labeled 1, that spans the entire length of the bar.  

5x 0.20=1                       5/1= 0.20

Step-by-step explanation:


Fynjy0 [20]2 years ago
4 0

Answer:

8 * 5 = 40

9/3 = 3

5 * 1/5 = 1

Do you agree?

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c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

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So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

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c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

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Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

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