The solution to that equation is p=500. What does the solution mean?

(1 point) According to the 1993 World Almanac, the number of calories a person walking at 3 mph burns per minute depends on the

ss7ja [257]

Burned 3 km or 5 hope it helps

4 0

2 years ago

Which real numbers are zeros of the function? f(x)=2x3−x2−8x+4 Select each correct answer. −2 −1 −12 0 12 1 2

Ede4ka [16]

Answer:

Step-by-step explanation:

Given is a function in x as

$f(x)=2x^3-x^2-8x+4$

We have to find the zeroes of the function

Since this is a cubic function this function has three zeroes.

Let us try to factorise this function by grouping two terms together.

$x^2(2x-1)-4(2x-1)\\= (2x-1)(x^2-4)$

= $(2x-1)(x-2)(x+2)$

Equate each factor to 0 to find zeroes as

$-2,2,\frac{1}{2}$

4 0

2 years ago

Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

Given:

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

Solving the equation:

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

Extraneous solutions:

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0

2 years ago

Read 2 more answers

ASAP PLEASE HELP!!

jenyasd209 [6]

Answer:

save up and pay cash

Step-by-step explanation:

paying cash is always the best idea and not trying to get so much debit. If you did one other otion and have the debit some emergency can come up and you will not be able to pay for that, and aying cash you save more money

5 0

2 years ago

Read 2 more answers

A car is traveling at a constant speed of 46 miles per hour. the formula for the distance traveled at the end of t hours is d=46

jonny [76]

d = 46t

First, let's find "d" for 7 hours.

d = 46(7)

d = 322 miles (7, 322)

Next, let's find "d" for 12 hours.

d = 46(12)

d = 552 miles (12, 552)

Finally, let's find "d" for 18 hours.

d = 46(18)

d = 828 miles (18, 828)

3 0

2 years ago