Ask question

Ask question

All categories

2 years ago

12

Which statement describes the vector plotted below?

1 answer:

Nimfa-mama [501]2 years ago

8 0

Answer:

A. The vector goes from (4, 0) to (3, -2).

Step-by-step explanation:

The tail of the vector is on the point (4, 0). The head of the vector is on the point (3, -2). Only answer choice A correctly identifies both of the points associated with the vector.

You might be interested in

Joseph squares a number and subtracts 8 from the answer. He then divides this result by 7. Finally he adds 12 and the result is

ivanzaharov [21]

Let the number be X, then we find
$( {x}^{2} - 8) \div 7 + 12 = 20$
$( {x}^{2} - 8) \div 7 = 8$
$( {x}^{2} - 8) = 56$
${x}^{2} = 64$
$x = \sqrt{64} \: \: \: \: \: x = - \sqrt{64}$
$x = 8 \: \: \: \: \: x = - 8$

5 0

2 years ago

1) Consider the sequence:

Ivan

Answer:

1) The 38th term is A. 38

2) The 11th term is D. 3072

3) The 3rd term is C. 34

Step-by-step explanation:

1) I added 2 until I got to the 38th term.

2) I multiplied until I got to the 11th term.

3) I added 3 until i got to the 12th term.

The teacher showed a more complex way to do it but this is just what I did.

I took the quiz, so I know that I got them all correct.

5 0

2 years ago

Read 2 more answers

Jeff Brown has collected sales data for his cupcake stand. Calculate the weighted moving average forecast for period 13 with wei

valentinak56 [21]

Answer:

Step-by-step explanation:

To calculate the weighted moving average for period 13 with weights 0.4 and 0.3.

P13 = (30.7x 0.4) + (42.0x 0.3)

P13 = 12.28 + 12.60

P13 = 24.88

6 0

2 years ago

What is the area of the shaded region?

azamat

Answer:

$(25\pi\ -24)\ cm^{2}$

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the circle minus the area of the two isosceles triangles

so

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

where r is the radius of the circle

In this problem we have

$r=5\ cm$

substitute

$A=\pi (5)^{2}$

$A1=25\pi\ cm^{2}$

Find the area of the two triangles

The area of the two isosceles triangles is equal to

$A=2[\frac{1}{2}bh]=bh$

we have

$b=6\ cm$

$h=5-1=4\ cm$

substitute

$A2=6*4=24\ cm^{2}$

Find the area of the shaded region

$A1-A2=(25\pi\ -24)\ cm^{2}$

5 0

2 years ago

Read 2 more answers

If ray JG is an angle bisector of ∠FJH, find m∠FJH.

miss Akunina [59]

Answer:

m∠FJH=60°

Step-by-step explanation:

The complete question is

JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°

What is FJH

we know that

m∠FJH=m∠FJG+m∠GJH -----> equation A

If ray JG is an angle bisector of ∠FJH

then

m∠FJG=m∠GJH -----> equation B

substitute the given values in equation B and solve for x

(2x + 4)°=(3x -9)°

3x-2x=4+9

x=13

Find the measure of angle FJH

m∠FJH=(2x + 4)°+(3x -9)°

substitute the value of x

m∠FJH=(2(13) + 4)°+(3(13) -9)°

m∠FJH=(30)°+(30)°

m∠FJH=60°

3 0

2 years ago