A remote ranch has a cylindrical water storage tank. It has a vertical central axis, a diameter of 16 ft, the sides are 5 ft hig
h, and it is full to the brim. The depth of this water is 4 ft. How much work (in ft-lb) would be required to pump all of the water over the upper rim? (Use the fact that water weighs 62.5 lb/ft3. Round your answer to the nearest integer.)
1 answer:
Answer and Step-by-step explanation:
Given: diameter = 16ft height = 5 ft. Depth = 4ft
Work =?
As we know that work = force x distance
W= distance x density x volume
W= ʃ04 (5-y) 62.5x ∏ (d/2)2dy (area = ∏r2 , r= d/2)
= 62.5 ʃ04 (5-y) ∏ (4y) dy
=62.5∏ ʃ04 (5-y) 4ydy
=62.5∏ ʃ04 20y-4y2dy
=62.5∏ |20y2/2 – 4y3/3|04
=62.5∏ |74.66|
=14659ft.lbs (approximately)
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Step-by-step explanation:
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Now, let's convert this to number of days because each day has 24*60=1440 minutes.
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We know 1 year has 12 months and one month has 30 days.
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Explanation: Since, according to the question- Perry takes time when he works alone = 3 hours
Similarly, Maria takes = 2 hours, While Lorna takes= 2 hours 30 minutes or 2.5 hours.
since, there are three people thus their are three possibility to choose any two of them.
1- when Perry and Maria work together then time taken by them is =
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2- when Maria and Lorna work together then time taken by them is = 10/9= 1 hours 1/9 minutes ≈ 1 hours 7 min
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Answer:
6 units
Step-by-step explanation:
Given: Points H and F lie on circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.
To find: Length of GH.
Sol: EC = CH = 9 (Radius of the same circle are equal)
Now, GC = GH + CH
GC = GH + 9
Now In ΔEGC, using pythagoras theorem,
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