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1 year ago

During a certain week, a post office sold Rs.280 worth of 14-paisas stamps. How many of these stamps did they sell?

1 answer:

6 0

So basically ...

You convert the rupees in paisas. One rupee is equal to one hundred paisas, so ...

280 × 100 = 28,000

And then we divide,

28,000 ÷ 14 = 2000

The post office sold 2000 stamps!

Hope this helped! :)

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The local skating rink pays marry a fixed rate per pupil plus a base amount to work as a skating instructor. she earns $90 for i

Ganezh [65]

You have to make a system of equations: lets make a equal the amount marry makes per student and b be her base amount.
90=15a+b (you have to subtract the top equation by the bottom equation)
62=8a+b (90-62=28, 15a-8a=7a, and b-b=0)
Since b canceled out, you are left with 7a=28 which means a=4. you can than plug a into the equation 62=8a+b to find that b=30.

since Lisa makes half of the base amount marry, her base amount is 15. However, she also make twice the amount per kid so she makes 8 per kid.
using the found values found you can make the equations (m=the amount Marry makes, l=the amount Lisa makes, and c is the number of children)
m=4c+30
l=8c+15
set c=20 and you should get m=110 and l=175. Based off of that information, we can say that Lisa makes more money instructing a class of 20 students.
I hope this helps.

8 0

1 year ago

A waiter at a restaurant has diarrhea what should happen?

Vilka [71]

The waiter should go home. It is because it is improper with regards to food safety and pathogenic bacteria such as E.coli can contaminate the food. Though the productivity of the restaurant will decrease, food safety must come first to reduce customer complaints.

8 0

1 year ago

∠C and ∠D are vertical angles with m∠C=−x+26 and m∠D=2x−10 . What is m∠D ?

Valentin [98]

Vertical angles are made by two intersecting lines .and they are always equal
<span>∠C and ∠D are equal.
so </span><span>−x+26 =2x-10
-3x=-36
x=36/3
x=12</span>°

∠D= 2x-10
put value of x here
∠D=24-10
∠D=14°

3 0

2 years ago

Read 2 more answers

Triangles ΔABC ≅ ΔBAD so that C and D lie in the opposite semi-planes of segment AB. Prove that segment CD bisects segment AD.

kolbaska11 [484]

Answer:

See explanation

Step-by-step explanation:

Triangles ΔABC and ΔBAD are congruent. So,

AB ≅ BA;
AC ≅ BD;
BC ≅ AD;
∠ABC ≅ ∠BAD;
∠BCA ≅ ∠ADB;
∠CAB ≅ ∠DBA.

Consider triangles AEC and BED. In these triangles,

AC ≅ BD;
∠EAC ≅ ∠EBD (because ∠CBA ≅ ∠BAD);
∠AEC ≅ ∠BED (as vertical angles).

So, ΔAEC ≅ ΔBED. Thus,

AE ≅ EB.

This means that segment CD bisects segment AD.

6 0

2 years ago

Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably in- finite, exh

mrs_skeptik [129]

Answer:

a) the negative integers set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = -n

b) the even integers set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = 2n

c) the integers less than 100 set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = 100 - n

d) the real numbers between 0 and 12 set A is uncountable.

e) the positive integers less than 1,000,000,000 set A is finite.

f) the integers that are multiples of 7 set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = 7n

Step-by-step explanation:

A set is finite when its elements can be listed and this list has an end.

A set is countably infinite when you can exhibit a one-to-one correspondence between the set of positive integers and that set.

A set is uncountable when it is not finite or countably infinite.

8 0

1 year ago