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kykrilka [37]
2 years ago
7

Bacteria begins to grow on the water's surface in a non-operational swimming pool on September 20. The bacteria grows and covers

the water's
surface in such a way that the area covered with bacteria doubles every day. If it continues to grow in this way, the water's surface will be
entirely covered with bacteria on September 28.
When will a quarter of the water's surface be covered?
O A.
The water's surface will be covered a quarter of the way on September 24.
B.
The water's surface will be covered a quarter of the way on September 26.
C.
The water's surface will be covered a quarter of the way on September 27.
OD. The water's surface will be covered a quarter of the way on September 25.​

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
6 0

Answer:

I think its A but im not to sure

Step-by-step explanation:

erik [133]2 years ago
6 0

Answer:

September 25th

Step-by-step explanation:

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A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i
SpyIntel [72]

we can use formula

f_L=f_s(\frac{v_a-v_p}{v_a+v_p} )

where

fL is listener frequency

fs is siren frequency

va is the speed of sound in air

vs is police car speed

so, we have

f_s=2000Hz

v_a=345m/s

v_p=65mph

now, we can change it into m/s

v_p=65*\frac{1609}{3600}m/s

v_p=29.05139m/s

now, we can plug it

f_L=2000(\frac{345-29.05139}{345+29.05139} )

f_L=1689.33263Hz..............Answer

3 0
2 years ago
during the _____ stage, the analyst will look for patterns of responses to the survey questions. a. data editing b. data collect
Masja [62]
C. data analysis. he would be analysing the patterns of responses.

8 0
2 years ago
How do you solve -9( -4r + 6s ) + 3s - 7(6s - 2r)
slavikrds [6]

Answer: 2.1 Pull out like factors :

6s - 2r  =   -2 • (r - 3s)

Equation at the end of step

 ((0-(9•(6s-4r)))+3s)--14•(r-3s)

Pulling out like terms

4.1     Pull out like factors :  6s - 4r  =   -2 • (2r - 3s)

Equation at the end of step

 ((0--18•(2r-3s))+3s)--14•(r-3s)

Final result :

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7 0
2 years ago
Izumi is running on a quarter-mile oval track. After running 110 yards, his coach records his time as 16 seconds.
pickupchik [31]

Answer:

14.04 miles per hour

Step-by-step explanation:

The problem is asking for Izumi's speed. The formula of speed is:

  • s = \frac{d}{t} , where "s" means speed, "d" means distance and "t" means time.

The problem is also asking for the unit<u> miles per hou</u>r (\frac{miles}{hour}) so, this means that we have to know how many miles Izumi ran, given that the problem only mentioned<u> yards (110 yards).</u>

Let's convert 110 yards to miles, provided that he Izumi ran 1,760 yards in a mile.

  • 110 yards ÷ 1760 \frac{yards}{mile} = 0.0625 miles (this is the distance covered by Izumi in miles)

Let's go back again to the formula: s = \frac{d}{t}

s = \frac{0.0625 miles}{16 seconds} = 0.0039 \frac{miles}{sec}

Since, the we arrived at a miles per second unit, we have to convert it to miles per hour.

So, if a minute has 60 seconds, then an hour has 3,600 seconds.

Thus, 0.0039 \frac{miles}{sec} × 3,600 \frac{seconds}{hour} = 14.04 miles per hour (the answer)

3 0
2 years ago
aron lei is making identical balloon arrangements for a party. He has 32 maroon balloons and 24 white balloons, he wants each ar
alexandr402 [8]

Answer:

The greatest number of arrangements that he can make if every balloon is used is 8.

Step-by-step explanation:

The greatest number of arrangements will be the greatest common factor between 24 and 32.

GCF of 24 and 32:

We keep factoring both numbers by prime factors, while they can both be divided by the same number. So

24 - 32|2

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6 - 8|2

3 - 4

There is no factor for which we can divide both 3 and 4. So the GCF is 2*2*2 = 8.

This means that the greatest number of arrangements that he can make if every balloon is used is 8.

5 0
2 years ago
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