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REY [17]
2 years ago
8

Point T is at (–3, 7). What are the coordinates of point T' after Ry-axis ∘ Rx-axis?

Mathematics
1 answer:
dimaraw [331]2 years ago
6 0

Given:

The point is T(-3,7).

To find:

The image T' after R_{y-axis}\circ R_{x-axis}.

Solution:

R_{y-axis}\circ R_{x-axis}, it means reflection across x-axis is followed by reflection across y-axis.

If a point is reflected across the x-axis, then

(x,y)\to (x,-y)

T(-3,7)\to T_1(-3,-7)

Then point is reflected across the y-axis. So,

(x,y)\to (-x,y)

T_1(-3,-7)\to T'(3,-7)

Therefore, the coordinates of point T' are (3,-7).

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Can someone help please??
Nady [450]

Answer:

The scores in order from least likely to most likely is 8, 3, 4, and 5.

Step-by-step explanation:

1. Calculate the probability of the spinner adding up to 1, 2, 3, 4, .... 8

You will get:

2 (1/16)

3 (2/16)

4 (3/16)

5 (4/16)

6 (3/16)

7 (2/16)

8 (1/16)

2. Given the scores from the problem, the probability of each number is 3 (2/16), 4 (3/16), 5 (4/16), and 8 (1/16).

3. With this, we can determine the scores in order from least likely to most likely is 8, 3, 4, and 5.

8 0
2 years ago
Manuel painted 0.75 of a rectangular banner green. After the paint dried, he painted 0.6 of the green area orange. What part of
NNADVOKAT [17]

Answer:

0.45 part of the banner is painted orange

Step-by-step explanation:

portion of rectangular banner painted green = 0.75

Portion of green painted part which is now painted orange = 0.60

Hence we can say that

0.6 part out of 0.75 part of total banner is painted orange

mathematically it is

0.6 * 0.75 = 0.45

Thus 0.45 part of banner is painted orange .

6 0
2 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
2 years ago
Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even
Elis [28]
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

4 0
2 years ago
You are a mechanic who is measuring the valve clearance on a motorcycle engine. The current clearance for one of the valves is 0
iren2701 [21]

Answer:

.

Step-by-step explanation:

5 0
1 year ago
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