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weeeeeb [17]
2 years ago
5

Es urgente ¡¡¡ si la MH de a y 4 es 6 y la MH de 8 y b es 12 calcula la MH de a y b

Mathematics
1 answer:
TiliK225 [7]2 years ago
7 0

Answer:

Sabemos que:

MH(x, y) = \frac{2xy}{x+y}

y tenemos que:

MH (a,4) = \frac{2*a*4}{a+4} = \frac{8*a}{a+4} = 6

Con esto podemos encontrar el valor de a:

8*a/(a+ 4) = 6

8*a = 6*(a + 4) = 6*a + 24

8a - 6a = 24

2a = 24

a = 24/2 = 12.

Tambien sabemos que:

MH(8,b) = \frac{2*8*b}{8+b} =\frac{16*b}{8+b} = 12

Y de ahí podemos despejar b:

(16*b)/(b + 8) = 12

16*b = 12*(b + 8) = 12b + 96

16b - 12b = 96

4b = 96

b = 96/4 = 24

Entonces tenemos a = 12 y b = 24, y el MH de a y b es:

MH(12,24) = 2*12*24/(12 + 24) = 24*24/36 = 16

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A forest ranger is in a forest 2 miles from a straight road. A car is located c miles down the road. The forest ranger can walk
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  • T(x) = (√(4+x^2))/2 +(c -x)/4
  • (a) x = 1.155 miles
  • (b) x = 1/2 mile

Step-by-step explanation:

The straight line distance from the starting point to the point x on the road is given by the Pythagorean theorem:

  d1 = √(2²+x²)

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  t1 = √(4+x²)/2

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  d2 = c - x . . . . . for c > x

and the corresponding time at 4 mph is ...

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__

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  T'(x) = x/(2√(4+x²)) -1/4

  0 = (2x -√(4+x²))/(4√(4+x²))

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  4 +x² = 4x² . . . . . . square both sides

  4/3 = x² . . . . . . . . . subtract x², divide by 3

  x = (2/3)√3 ≈ 1.1547

If c = 9 miles, x = 1.1547 miles.

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(b) For c < (2/3)√3, the shortest travel time will be along the straight-line path to the car.

If c = 1/2 mile, x = 1/2 mile.

8 0
2 years ago
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