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2 years ago

Es urgente ¡¡¡ si la MH de a y 4 es 6 y la MH de 8 y b es 12 calcula la MH de a y b

Mathematics

1 answer:

TiliK225 [7]2 years ago

7 0

Answer:

Sabemos que:

$MH(x, y) = \frac{2xy}{x+y}$

y tenemos que:

$MH (a,4) = \frac{2*a*4}{a+4} = \frac{8*a}{a+4} = 6$

Con esto podemos encontrar el valor de a:

8*a/(a+ 4) = 6

8*a = 6*(a + 4) = 6*a + 24

8a - 6a = 24

2a = 24

a = 24/2 = 12.

Tambien sabemos que:

$MH(8,b) = \frac{2*8*b}{8+b} =\frac{16*b}{8+b} = 12$

Y de ahí podemos despejar b:

(16*b)/(b + 8) = 12

16*b = 12*(b + 8) = 12b + 96

16b - 12b = 96

4b = 96

b = 96/4 = 24

Entonces tenemos a = 12 y b = 24, y el MH de a y b es:

MH(12,24) = 2*12*24/(12 + 24) = 24*24/36 = 16

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