Answer:
27 hours
Step-by-step explanation:
The regular hours are paid normally, 21/hr hence working for 40 hours, Michael earns 40*21=$840
To work x hours paid overtime as 1.5 of the normal rate, the rate would be $21*1.5=$31.5/hr
X hours multiplied by rate of $31.5/hr should be at least equal to $840
31.5x>=840
X>=840/31.5>=26.6667 hours and when rounded off
X is 27 hours
Hello there,
To find out the equation you use the slope intercept form...
y = mx + b
M is the slope and b is where the line crosses the y-axis...
Now to find the slope you count the distance from two points so...
The distance from (0,2) to (1,5) is 3 units up and 1 unit over.
So the correct answer should be...
y = 3x + 2
Answer: w = 3z + 2
Hope I helped!!
-Char
Each angle has a sin, cos, and tan associated with it.
in a right angled triangle there are two other angles which each have ratios.
Answer:
0.08 ounces is interpreted as the Mean Absolute Deviation and this means that
the various weights of each of the 48 eggs deviates from the mean of the egg (2.1 ounces)by 0.08 ounces.
Step-by-step explanation:
Mean Absolute Deviation of a data set is defined as the distance or the deviation between a given data set and the calculated mean.
Mean Absolute Deviation tells us about how much a data set varies from it's mean.
From the above question, we are told that after weighing 48 eggs we have a mean of 2.1 ounces and mean deviation of 0.08 ounces
Therefore this means that the various weights of each of the 48 eggs deviates from the mean of the egg (2.1 ounces)by 0.08 ounces
Answer:
<em>H₀</em>: <em>μ</em>₁ = <em>μ</em>₂ vs, <em>Hₐ</em>: <em>μ</em>₁ > <em>μ</em>₂.
Step-by-step explanation:
A two-sample <em>z</em>-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.
It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.
The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:
<em>H₀</em>: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. <em>μ</em>₁ = <em>μ</em>₂.
<em>Hₐ</em>: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. <em>μ</em>₁ > <em>μ</em>₂.
The significance level of the test is:
<em>α</em> = 0.05.
The test is defined as:
The decision rule for the test is:
If the <em>p</em>-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.
