Answer:
Step-by-step explanation:
Let suppose that one of the radii meets the circle at the point (1,0). The straight line distance formula is:
Answer: A. A(1) = 14; A(n) = (n − 1) −4; A(n) = 14 + (n − 1)(−4)
Step-by-step explanation:
Arithmetic sequence is a sequence that is identified by their common difference. Let a be the first term, n be the number of terms and d be the common difference.
For an arithmetic sequence, common difference 'd' is added to the preceding term to get its succeeding term. For example if a is the first term of a sequence, second term will be a+d, third term will give a+d+d and so on to generate sequence of the form,
a, a+d, a+3d, a+4d...
Notice that each new term keep increasing by a common difference 'd'
The nth term of the sequence Tn will therefore give Tn = a+(n-1)d
If the initial (first) term is 14 and common difference is -4, the nth of the sequence will be gotten by substituting a = 14 and d = -4 in the general formula to give;
Tn = 14+(n-1)-4 (which gives the required answer)
Tn = 14-4n+4
Tn = 18-4n
Answer: The value of x- 2y is a. 
.
Step-by-step explanation:
Given: x and y are two positive real numbers such that 
and 
.
Consider ![(x-2y)^2=x^2-2(x)(2y)+(2y)^2\ \ \ [(a+b)^2=(a^2-2ab+b^2)]](https://tex.z-dn.net/?f=%28x-2y%29%5E2%3Dx%5E2-2%28x%29%282y%29%2B%282y%29%5E2%5C%20%5C%20%5C%20%5B%28a%2Bb%29%5E2%3D%28a%5E2-2ab%2Bb%5E2%29%5D)
Put and , we get
Taking square root on both sides , we get'
Hence, the value of x- 2y is a. .
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
