Answer:
4:120
Step-by-step explanation:
for 120 student they would be 4 teacher needed per 30 student
4:120
Answer: a) 0.25, b) 0.78, c) 0.71
Step-by-step explanation:
Since we have given that
Number of employees in marketing = 4
Number of employees in management = 7
We need to hire committee of 3 people.
a) Find the probability that the committee has exactly 2 employees from marketing.
So, Probability becomes

b) Find the probability that the committee has at least one employee from marketing.

c) Find the probability that the committee has at most one employee from management.

Hence, a) 0.25, b) 0.78, c) 0.71
Answer:
The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).
Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:
-6/4 + 1/4 = -5/4.
Now i will give some other examples:
Now, if the distance between ticks is 2/4, then the number at the right will be:
-6/4 + 2/4 = -4/4 = -1
Now, if the distance between ticks is 3/4, the the number at the right will be:
-6/4 + 3/4 = -3/4.
Answer:
The customer saves 5.9 - 5.5 = $0.5
when he shops at store B
Step-by-step explanation:
Stores A and B sells bananas at different prices per pound.
Bananas are being sold for $0.59 a pound at Store A and $0.55 a pound at Store B.
If a customer wants to buy 10 pounds of bananas from store A and store B,
The customer would spend 0.59 × 10 pounds of bananas = $5.9
buying from store A and
The customer would spend 0.55 × 10 pounds of bananas = $5.5
buying from store B.
The customer spends more for 10 pounds of bananas if he buys from shop A.
The customer saves 5.9 - 5.5 = $0.5
when he shops at store B
Answer:
- 880 lbs of all-beef hot dogs
- 2000 lbs of regular hot dogs
- maximum profit is $3320
Step-by-step explanation:
We can let x and y represent the number of pounds of all-beef and regular hot dogs produced, respectively. Then the problem constraints are ...
- .75x + 0.18y ≤ 1020 . . . . . . limit on beef supply
- .30y ≤ 600 . . . . . . . . . . . . . limit on pork supply
- .2x + .2y ≥ 500 . . . . . . . . . . limit on spice supply
And the objective is to maximize
p = 1.50x + 1.00y
The graph shows the constraints, and that the profit is maximized at the point (x, y) = (880, 2000).
2000 pounds of regular and 880 pounds of all-beef hot dogs should be produced. The associated maximum profit is $3320.