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Savatey [412]
2 years ago
5

Pietro made 18 baskets during a basketball game.The number of 3 pointers are 3 more than half of the 2 point shots.how many type

s of each shot did he make.How many total points did he get.
Mathematics
1 answer:
blagie [28]2 years ago
5 0

Total points is 23

<u>Explanation:</u>

Given:

Total number of baskets = 18

Let the number of 2 pointer shots be x

Let the number of 3 pointer shots be y

According to the question:

y = \frac{x}{2} + 3                  -1

The equation can be formed as:

\frac{x}{2} + 3 + x = 18

On solving this equation further we get:

\frac{x+6+2x}{2} = 18\\\\9x = 36\\\\x = 4

Putting the value of x = 4 in equation 1

y = \frac{x}{2}+3\\ \\y = \frac{4}{2} + 3\\\\y = 5

Points for 2 pointer shots = 4 X 2

                                        = 8

Points for 3 pointer shots = 5 X 3

                                        = 15

Total points = 8 + 15

                  = 23

Therefore, total points is 23

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Answer:

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Step-by-step explanation:

Proportion of California residents who reported insufficient rest = 8.0%

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p'₁ = 0.08 * 11545 =923.6

p'₂ = 0.088 * 4691=412.81

σ₁ = \sqrt{n*p_1*q_1}  = \sqrt{n*p_1*(1-p_1)} = \sqrt{11545*0.08*(1-0.08)} = 29.15

σ₂ = \sqrt{n*p_2*q_2}  = \sqrt{n*p_2*(1-p_2)}= \sqrt{4691*0.088*(1-0.088)} = 19.40

Samples size of California residents n₁ = 11,545

Samples size of Oregon residents n₂ = 4,691

Hypothesis can be constructed thus

Let our null hypothesis be H ₀: p'₁ = p'₂

and alternative hypothesis H ₐ: p'₁ ≠ p'₂

Then we have  

z =\frac{(p'_1 -p'_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2} } }

The test statistics can be computed by

     

t₀ = \sqrt{\frac{n_1n_2(n_1+n_2-2)}{n_1+n_2} } *\frac{p_1'-p_2'}{\sqrt{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2} } =      1104.83

c from tables is   P(T ≤ c) = 1 - α where α = 5% and c = 1.65

since t₀ ≥ c then then the hypothesis is rejected which means the alternative hypothesis is rejected

b. Type I error, rejecting a true hypothesis

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A botanist collected one leaf at random from each of 10 randomly selected mature maple trees of the same species. The mean and t
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Answer:

One sample t-test for population mean would be the most appropriate method.

Step-by-step explanation:

Following is the data which botanist collected and can use:

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One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.

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At a rally attended by 520 people, 30% were fantes, 25% were ewes, 15% were nzemas, 20% were gas and the rest were gonjas. How m
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Answer:

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Step-by-step explanation:

Total no. of people = 520

No. of fantes = \frac{30}{100} × 520

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No. of ewes = \frac{25}{100} × 520 = 130

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No. of more nzemas than fantes = 156 - 78 = 78

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