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2 years ago

15

The formula for the distance traveled over time ttt and at an average speed vvv is v\cdot tv⋅tv, dot, t. Amit ran for 404040 min

utes at a speed of about 555 kilometers per hour. What calculation will give us the estimated distance Amit ran in kilometers?

1 answer:

andrew-mc [135]2 years ago

4 0

Answer:

5 x 40/60

Step-by-step explanation:

khan explanation

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If a new star appeared in our solar system that was larger and heavier than the Sun, the planets would MOST LIKELY

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Answer:

C

Step-by-step explanation:

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4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

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The second sample size is $n_2 = 32$

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The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

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Generally the degree of freedom is mathematically represented as

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$\alpha = (C - 100 )\%$

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=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

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So

$t_c = 2 * 1.67$

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given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

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Answer:

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