so I need to do a list of numbers like this:
98, 100, 102, 104, 106, 108, 110.
104 is the median number
add 98+100+102+104+106+108+110=728
divide by seven 728 / 7 = 104
so the difference between the median 104 and the avarage 104 is 0 they are
104=104
hope this helps
7 and 1/8. all you need to do is add these together by getting a common denominator of eight
Answer:
<u>The original three-digit number is 417</u>
Step-by-step explanation:
Let's find out the solution to this problem, this way:
x = the two digits that are not 7
Original number = 10x+7
The value of the shifted number = 700 + x
Difference between the shifted number and the original number = 324
Therefore, we have:
324 = (700 + x) - (10x + 7)
324 = 700 + x - 10x - 7
9x = 693 - 324 (Like terms)
9x = 369
x = 369/9
x = 41
<u>The original three-digit number is 417</u>
