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1 year ago

Find the following angle measures. mEAD = ° mCAB = °

Mathematics

2 answers:

Dimas [21]1 year ago

8 0

29 and 119
Just did it :(

sergejj [24]1 year ago

6 0

Part 1) Find m∠EAD

we know that

m∠EAD+m∠DAF+m∠BAF= $180\°$ ----> by supplementary angles

solve for m∠EAD

m∠EAD= $180\°$ -(m∠DAF+m∠BAF)

in this problem we have

m∠DAF= $90\°$

m∠BAF= $61\°$

substitute in the formula above

m∠EAD= $180\°-90\°-61\°=29\°$

therefore

the answer part 1) is

m∠EAD= $29\°$

Part 2) Find m∠CAB

we know that

m∠CAB+m∠BAF= $180\°$ --------> by supplementary angles

solve for m∠CAB

m∠CAB= $180\°$ -m∠BAF

in this problem we have

m∠BAF= $61\°$

substitute in the formula above

m∠CAB= $180\°-61\°=119\°$

therefore

the answer part 2) is

m∠CAB= $119\°$

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kykrilka [37]

Answer:

0.0045 = 0.45% probability that less than two of them ended in a divorce

Step-by-step explanation:

For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

55% of marriages in the state of California end in divorce within the first 15 years.

This means that $p = 0.55$

Suppose 10 marriages are randomly selected.

This means that $n = 10$

What is the probability that less than two of them ended in a divorce?

This is

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.55)^{0}.(0.45)^{10} = 0.0003$

$P(X = 1) = C_{10,1}.(0.55)^{1}.(0.45)^{9} = 0.0042$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0003 + 0.0042 = 0.0045$

0.0045 = 0.45% probability that less than two of them ended in a divorce

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1 year ago

What is the product of 8x-3 and x2- 4x +8

Dmitriy789 [7]

A product is the answer that you get when you multiply numbers together. So for this problem, you have 2 groups to multiply together. Since I cannot show a square or cubed x, I will put an x2 for x squared and an x3 for x cubed. You have to multiply each number in the first parentheses by each number in the second parentheses. Then combine any like sets.

(8x-3)(x2-4x+8)
8x3-32x2+64x-6x+12x-24
8x3-32x2+70x-24

So the answer is 8x cubed minus 32x squared plus 70x minus 24. Whew! That's a long one. Hope I didn't miss anything.

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1 year ago

Corinne and Aretha are having a 26-mile race. Corinne gave Aretha a head start by letting her begin 3.5 miles in front of the st

Ronch [10]

From the table, the speed of Corinne is given by

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From the graph, the speed of Aretha is given by

$speed=slope= \frac{5.5-4.5}{20-10} = \frac{1}{10} =0.1 \ miles / minute$

The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t

Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then

0.125t = 3.5 + 0.1t
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t = 3.5 / 0.025 = 140

Therefore, the number of minutes after the start of the race that Corinne will catch Aretha is 140 minutes.

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2 years ago

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Afina-wow [57]

Ho ho ho, lets get this party started
ok so I'm just really excited to use this stuff that I just learned

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so
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1 year ago

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stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

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