Find the following angle measures. mEAD = ° mCAB = °
2 answers:
<u>Part 1)</u> Find m∠EAD
we know that
m∠EAD+m∠DAF+m∠BAF= ----> by supplementary angles
solve for m∠EAD
m∠EAD=-(m∠DAF+m∠BAF)
in this problem we have
m∠DAF=
m∠BAF=
substitute in the formula above
m∠EAD=
therefore
<u>the answer part 1) is </u>
m∠EAD=
<u>Part 2)</u> Find m∠CAB
we know that
m∠CAB+m∠BAF= --------> by supplementary angles
solve for m∠CAB
m∠CAB=-m∠BAF
in this problem we have
m∠BAF=
substitute in the formula above
m∠CAB=
therefore
<u>the answer part 2) is</u>
m∠CAB=
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and number of LFG = y
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Total Score = 2x+3y
Also, Total score = 36 (given in the question)
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when SFG=0, then x=0 and so 3y=36.
y=12 i.e. LFG = 12
So the extreme case is (0,12) i.e. SFG=0 and LFG=12.
Other cases would be integral vales of (x,y) which satisfy the equation 2x+3y=36.
So (3,10) , (6,8) , (9,6) , (12,4) , (15,2) , and (18,0) are other cases.
Hence final answers are (x,y) = (0,12) , (3,10) , (6,8) , (9,6) , (12,4) , (15,2) , and (18,0)
Let's assume number of SFG = x
and number of LFG = y
Given that 2 points for a short field goal, and 3 points for a long field goal.
Total Score = 2x+3y
Also, Total score = 36 (given in the question)
So we have the equation
where x and y are integers.
when SFG=0, then x=0 and so 3y=36.
y=12 i.e. LFG = 12
So the extreme case is (0,12) i.e. SFG=0 and LFG=12.
Other cases would be integral vales of (x,y) which satisfy the equation 2x+3y=36.
So (3,10) , (6,8) , (9,6) , (12,4) , (15,2) , and (18,0) are other cases.
Hence final answers are (x,y) = (0,12) , (3,10) , (6,8) , (9,6) , (12,4) , (15,2) , and (18,0)
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