12h + 30w.....where h = hrs worked and w = wagons sold
so if an employee works 6 hrs and sells 3 wagons....then h = 6 and w = 3
12h + 30w
12(6) + 30(3) =
72 + 90 = $ 162 <==
Answer:
<h2>The answer is 0.23(approx).</h2>
Step-by-step explanation:
The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.
We need to find the probability of getting exactly 3s as the result.
From the sequence of 6 independent rolls, 2 rolls can be chosen in
ways.
The probability of getting two 3 as outcome is
.
In the rest of the 4 sequences, will not be any 3 as outcome.
Probability of not getting a outcome rather than 3 is
.
Hence, the required probability is
≅0.2966 or, 0.23.
7 3/4 × 3/4 = So u add 3×3=9
Then add 4×4=16 Give you 9/16
Then you add that 7 you left out with 9/16
But just the 9 not the 16
7 × 9 = 63 And your answer is 63/16
Hope i help :-)