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2 years ago

What is the total surface area of the square pyramid below? question above

Mathematics

1 answer:

Wewaii [24]2 years ago

8 0

Answer:

132 m².

Step-by-step explanation:

What's the surface area of each lateral face of this pyramid?

Each lateral face of this pyramid is a triangle, with

a height of 8 meters
on a base 6 meters.

The base of this pyramid is a square. As a result, all four lateral sides are congruent. The area of each of these triangle is thus

$\displaystyle \frac{1}{2}\times \text{Base}\times \text{Height} = \rm \frac{1}{2} \times 6 \times 8 = 24\; m^{2}$ .

The base of this pyramid is a square. The length of a side of this square is 6 meters. The area of the base will be

$\text{Side}^{2} = \rm 6^{2} = 36\; m^{2}$ .

Put the five faces together to get the total surface area of this square pyramid:

$\rm 4\times 24 + 36 = 132\; m^{2}$ .

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Answer:

Rounding to the nearest tenth and rounding to the nearest one hundredth.

Step-by-step explanation:

round all up or down then line up and add

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2 years ago

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What are the domain, range, and asymptote of h(x) = 6x – 4? domain: {x | x is a real number}; range: {y | y > 4}; asymptote:

Mkey [24]

Answer:

Step-by-step explanation:

The domain of a function is the set for which the function is defined. Our function is the function $h(x) = 6x-4$ . This function is defined regardless of the value of x, so it is defined for every real value of x. That is, it's domain is the set {x|x is a real number}.

The range of the function is the set of all possible values that the function might take, that is {y|y=6x-4}. Recall that every real number y could be written of the form y=6x-4 for a particular x. So the range of the function is the set {y|y is a real number}.

Note that as x gets bigger, the value of 6x-4 gets also bigger, then it doesn't approach any particular number. Note also that as x approaches - infinity, the value of 6x-4 approaches also - infinity. In this case, we don't have any horizontal asymptote. Since the function is defined for every real number, it doesn't have any vertical asymptote. Since h is a linear function, it cannot have any oblique asymptote, then h doesn't have any asymptote.

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2 years ago

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A farmer kept 96 kilograms of animal feed in his barn.

lesya692 [45]

Answer:

<em>The amount of animal feed left was 86.4 kilograms.</em>

Step-by-step explanation:

Initial amount of animal feed in the barn was 96 kilograms.

The barn leaked and $\frac{1}{10}$ of the feed was wasted.

So, <u>the amount of feed wasted</u> $=\frac{1}{10}(96)=9.6$ kilograms.

<em>Now, for finding the amount of feed that was left, we need to subtract the amount of wasted feed from the initial amount of feed.</em>

So, the amount of animal feed left $=(96-9.6)\ kilograms=86.4\ kilograms$

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2 years ago

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The gas mileage for a certain vehicle can be approximated by m=−0.05x2+3.5x−49, where x is the speed of the vehicle in mph. Dete

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Answer:

Step-by-step explanation:

Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;

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when m= 9

9 = −0.05x²+3.5x−49

−0.05x²+3.5x−49 = 9

0.05x²-3.5x+49 = -9

Multiplying through by 100

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Dividing through by 5;

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x²+70x−1160 = 0

Using the general formula to get x;

a = 1, b = 70, c = -1160

x = -70±√70²-4(1)(-1160)/2

x = -70±√4900+4640)/2

x = -70±(√4900+4640)/2

x = -70±√9540/2

x = -70±97.7/2

x = -70+97.7/2

x = 27.7/2

x = 13.85mph

x ≈ 14 mph

Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph

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Answer:

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Step-by-step explanation:

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What is the total surface area of the square pyramid below? question above ​

What is the total surface area of the square pyramid below? question above