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Sidana [21]
1 year ago
11

I need help pls,

Mathematics
2 answers:
babymother [125]1 year ago
8 0

Answer:

$0.40 for each bottle of juice

Step-by-step explanation:

Alisiya [41]1 year ago
6 0
Take the total number $8.62 and subtract the amount for the apples $2.62 from it to get the cost of the 15-pack of juice bottles $6.00. Now divide 6 by 15 to get how much each bottle of juice would costs not including tax $0.40.

$0.40 is your answer.

Hope this helps!!
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Ming-Li spent $15 at the movies. She then earned $30 babysitting . She spent $12 at the bookstore. She now has $18 left . How mu
Musya8 [376]
Ming-Li had $75 to begin with. Just add all the numbers
8 0
2 years ago
Read 2 more answers
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
2 years ago
Let P be a point not on the line L that passes through the points Q and R. The distance d from the point P to the line L is d =
Goshia [24]

Answer:

Distance from point (0,1,1) to the given line is zero.

Step-by-step explanation:

Given parametric equations of line,

x=2t, y=5-2t, z=1+t

To find distance from (0,1,1), we have to eliminate t from above equations so that,

y=5-2t=5-x\implies x+y=5=4+1=4+z-t=4+z-\frac{1}{2}x

\implies 3x+2y-2z-8=0\hfill (1)

whose direction ratioes are (l,m,n)=(3,2,-2) and distance fro point (a,b,c)=(0,1,1) is given by,

\frac{al+bm+cn}{\sqrt{l62+m^2+n^2}}=\frac{(3\times 0)+(2\times 1)+(-2)(1)}{\sqrt{3^2+2^2+(-2)^2}}=\frac{0+2-2}{\sqrt{17}}=0

Distance between point (0,1,1) and (1) is zero. That is point 90,1,1) is lies on the line (1).

8 0
2 years ago
1- Caleb's family room has the dimensions shown. He needs to find the area of the room so that he knows how much carpet to buy.
Rina8888 [55]

Answer: 20\frac{11}{32}\ sq\ yd


Step-by-step explanation:

Given: The width of the room =3\frac{7}{8}\ yd=\frac{31}{8}\ yd

The length of the room =1\frac{5}{4}\ yd=\frac{21}{4}\ yd

The area of the rectangular room= length \times width

⇒The area of the rectangular room= \frac{21}{4}\times\frac{31}{8}\ sq\ yd

⇒The area of the rectangular room= \frac{651}{32}\ sq\ yd

⇒The area of the rectangular room= 20\frac{11}{32}\ sq\ yd


5 0
2 years ago
Read 2 more answers
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
2 years ago
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