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2 years ago

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The graph of f(x) = StartRoot x EndRoot is reflected over the y-axis. Use the graphing calculator to graph this reflection. Whic

h list contains three points that lie on the graph of the reflection? (–81, 9), (–36, 6), (–1, 1) (1, –1), (16, –4), (36, –6) (–49, 7), (–18, 9), (–1, 1) (1, –1), (4, –16), (5, –25)

1 answer:

labwork [276]2 years ago

7 0

Answer:

<em>(–81, 9), (–36, 6), (–1, 1) </em> are the correct three points.

Step-by-step explanation:

Given the function:

$f(x) =\sqrt x$

Please refer to the attached image.

The green line shows the graph of actual function.

It is reflected over y axis.

The reflected graph is shown in black color in attached image.

When reflected over y axis, the sign of variable $x$ changes from Positive to Negative.

So, the resultant function becomes:

$f(x)=\sqrt{-x}$

i.e. we will have to give the values of x as negative now.

so, the options in which value of x is negative are the possible answers only.

The possible answers are:

(–81, 9), (–36, 6), (–1, 1) and

(–49, 7), (–18, 9), (–1, 1)

Now, we will check the square root function condition.

In the 2nd option, (–18, 9) does not satisfy the condition.

So, the correct answer is:

<em>(–81, 9), (–36, 6), (–1, 1)</em>

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"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

sergiy2304 [10]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

<em />

<em>Let </em> $p_1$ <em> = proportion of drivers that were in compliance initially</em>

$p_2$ <em> = proportion of drivers that were in compliance one year later</em>

(a) <u>Null Hypothesis</u>, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

<u>Alternate Hypothesis</u>, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is <u>Two-sample z proportion statistics</u>;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers in compliance initially = 98.9%

$\hat p_2$ = sample proportion of drivers in compliance one year later = 96.9%

$n_1$ = sample of drivers initially = 1,250

$n_2$ = sample of drivers one year later = 1,100

(b) So, <u><em>the test statistics</em></u> = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

= 3.33

<u>Now, P-value of the test statistics is given by;</u>

P-value = P(Z > 3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.99957 = <u>0.00043</u>

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis.</em></u>

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0

2 years ago

A vehicle with a particular defect in its emission control system is taken to a succession of randomly selected mechanics until

IrinaK [193]

Answer:

the mle of P=0.833

Step-by-step explanation:

X=incorrect answer

And probability of success to be denoted as P

Here X posses a binomial distribution along with 'r' and 'p'parameter

CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION

3 0

2 years ago

Find the midpoint of the segment between the points (3,17) and (−14,−8)

mixas84 [53]

Answer:

$\large\boxed{\left(-\dfrac{11}{2},\ \dfrac{9}{2}\right)}$

Step-by-step explanation:

The formula of a midpoint between two points A(x₁, y₁) and B(x₂, y₂):

$M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

We have the points (3, 17) and (-14, -8).

Substitute:

$M(x,\ y)\\\\x=\dfrac{3+(-14)}{2}=\dfrac{-11}{2}\\\\y=\dfrac{17+(-8)}{2}=\dfrac{9}{2}$

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2 years ago

Read 2 more answers

The table lists recommended amounts of food to order for 25 party guests. Amanda and Syndey are hosting a graduation party for 4

yan [13]

Answer:

Answer: 25 guests is 2.5 times more than 10

Multiply each order by 2.5

Chicken = 16 x 2.5 = 40

Lasagna = 7 x 2.5 = 17.5 , round to 18

Deli meat = 1.8 x 2.5 = 4.5, round to 5

Sliced cheese = 15 x 2.5 = 37.5, round to 38

Buns = 1 x 2.5 = 2.5, round to 3

Potato salad = 2 x 2.5 = 5

Step-by-step explanation:

7 0

2 years ago

Question 6: An experiment consists of throwing two six-sided dice and observing the number of spots on the upper faces. Determin

yaroslaw [1]

Answer:

(a) 0.25

(b) 0.944

(c) 0.444

(d) 0.167

Step-by-step explanation:

There are six possible outcomes for each die, which means that the number of possible outcomes is:

$n=6*6 = 36$

(a) In order for each die to show four or more spots they will both have to land on a four, five or six. The probability of this happening is:

$P(A) = \frac{3*3}{36}=0.25$

(b) There are only two possible outcomes for which the sum is three (1 and 2, or 2 and 1). The probability of the sum NOT being three is:

$P(B) = 1-\frac{2}{36}=0.944$

(c) If neither a one or a six must appear, then there are 4 possible outcomes for each die, the probability is:

$P(C) = \frac{4*4}{36}=0.444$

(d) For each one of the six possible numbers on the first die, there is only one on the second die for which the sum of the spots is 7, totaling six possible ways to sum 7:

$P(D) = \frac{6}{36}=0.167$

7 0

2 years ago