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tekilochka [14]
2 years ago
8

Vanessa is a caterer. She made several batches of appetizers last weekend for an event. This weekend, Vanessa made 4 times as ma

ny batches. She made a total of 25 batches of appetizers for the two weekends. Determine the number of batches
Vanessa made last weekend and the number of batches she made this weekend.
Let b = the number of batches of appetizers Vanessa made last weekend.
Mathematics
2 answers:
galina1969 [7]2 years ago
8 0

Answer:

100 x 13/16 x 25b = 4

18 3/4 = 25b/4  

b=25/4

b= 6.25

Step-by-step explanation:

25/4 = 6 1/4 last weekend and 18 3/4 this weekend.

katrin2010 [14]2 years ago
3 0

Answer: Vanessa made 5 batches last weekend and 20 batches this weekend.

Step-by-step explanation:

We have that Vanessa made b batches last weekend, and we know that this weekend she made 4 times as many as the past weekend, so this weekend she made 4*b batches.

In the two weekends, she made a total of 25 batches: this means that:

b + 4*b = 25

5*b = 25

b = 25/5 = 5

then Vanessa made 5 batches last weekend, and 4*5 = 20 batches this weekend.

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We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

For k=5

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

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For k=6

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

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