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Answer with explanation:</h2>
Given : An urn contains 2 red marbles and 3 blue marbles.
Total marbles = 2+3=5
a) The general ways in which the person could get a red marble and a blue marble are :
1) He draws red marble first and then second marble as blue.
2) He draws blue marble first marble and then second marble as red.
b) The number of ways to get one red and one blue marble is given by :-
(i)
c) Number of ways to get 2 marbles from 5 is given by :-
(ii)
Now, The probability the person gets a red and a blue marble will be :-
[Divide (i) by (ii)]
Hence, the probability the person gets a red and a blue marble= 0.6
Answer:
Here, BRX and NJY are two triangles in which,
BR = 30 cm, RX = 40 cm, BX = 60 cm, NJ = 15 cm, JY = 20 cm and NY = 30 cm,
Also, m∠B = m∠N, m∠R = m∠J and m∠X = m∠Y,
By the property of congruence,
, 
and 
Thus, By AAA similarity postulate,
Hence, proved.
Answer:
C. Also, known as the 3rd one.
Step-by-step explanation:
Answer: We have two solutions:
1000 - 998 = 2
1001 - 999 = 2
Step-by-step explanation:
So we have the problem:
****-*** = 2
where each star is a different digit, so in this case, we have a 4 digit number minus a 3 digit number, and the difference is 2.
we know that if we have a number like 99*, we can add a number between 1 and 9 and we will have a 4-digit as a result:
So we could write this as:
1000 - 998 = 2
now, if we add one to each number, the difference will be the same, and the number of digits in each number will remain equal:
1000 - 998 + 1 - 1 = 2
(1000 + 1) - (998 + 1) = 2
1001 - 999 = 2
now, there is a trivial case where we can find other solutions where the digits can be zero, like:
0004 - 0002 = 2
But this is trivial, so we can ignore this case.
Then we have two different solutions.
