Answer:
Step-by-step explanation:
we know that
In the right triangle ABC
The function sine of angle 68 degrees is equal to divide the opposite side SB by the hypotenuse AC
so
substitute the values and solve for AC
What is the angle above the x axis (i.e., "north of east") for a vector with components (15 m, 8 m)?
2 answers:
Answer:28.071
Step-by-step explanation:
Given
vector component is (15,8)
i.e. its x component is 15 from origin and y component is 8 m
So angle made by vector with x axis is
If you draw out the two components in a head-to-nose fashion, you will create a right angle triangle something like the picture, that is if I interpreted the information right (the way I interpreted it is 15m east and 8m north);
The dotted line represents the x-axis;
Θ represents the desired angle;
Using trigonometry, we can create and solve an equation to get the angle (Θ);
In this case, you can use use sin or cos, I'll go with sin:
SinΘ = opp/hyp
SinΘ = 8/15
Θ = Sin⁻¹(8/15)
= 32.23.... ⇒ 32.2°
The dotted line represents the x-axis;
Θ represents the desired angle;
Using trigonometry, we can create and solve an equation to get the angle (Θ);
In this case, you can use use sin or cos, I'll go with sin:
SinΘ = opp/hyp
SinΘ = 8/15
Θ = Sin⁻¹(8/15)
= 32.23.... ⇒ 32.2°
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Answer:
a) 10/3
b) hyperbola
c) x = ± 6/5
Step-by-step explanation:
a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:
Given the conic equation:
We have to make it to be in the form :
Comparing with
e = 10/3 = 3.3333, p = 6/5
b) since the eccentricity = 3.33 > 1, it is a hyperbola
c) The equation of the directrix is x = ±p = ± 6/5