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spayn [35]
2 years ago
8

An object in a simulation accelerates from rest to a speed of 4 meters per second in 2 seconds. It then accelerates linearly for

the next 3 seconds until it reaches 10 meters per second. The object remains at that speed (acceleration = 0) for 3 seconds and then de-accelerates linearly until it comes to rest 2 seconds later. Which graph demonstrates the speed of the object for those 10 seconds?

Mathematics
2 answers:
k0ka [10]2 years ago
8 0
Since you did not give the choices for which graph it represent, i will just describe what will it look like. for time 0 - 2 s , it will go diagonally upward until it reach at 4 m/s in the y axis. then from 2 - 5 sit will go diagonally upward until it reach at 10 m/s in the y axis. then from 5 - 8 s will be horizontal. then it will go diagonally downwards 
sdas [7]2 years ago
5 0

Answer:

It is given that:

  • An object in a simulation accelerates from rest to a speed of 4 meters per second in 2 seconds.

It means that the graph increases continuously from rest to 10 meters in  2 seconds. so the graph will be a straight line from t=0 to t=2 and reach speed=4.

  • It then accelerates linearly for the next 3 seconds until it reaches 10 meters per second.

i.e. again we will get a straight line joining at t=2 speed=4 and at t=5 speed=10

  • The object remains at that speed (acceleration = 0) for 3 seconds and then de-accelerates linearly until it comes to rest 2 seconds later.

i.e. the speed is then constant between 5 seconds to 8 seconds i.e. we get a horizontal line at speed=10 meters per second and then we will get a straight line decreasing linearly and reaching speed=0 from t=8 seconds to t=10 seconds.

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Answer:

a. y equals one third times x plus 10

= y = 1/3(x) + 10

Step-by-step explanation:

Let us represent:

Let the original final plan = x

Let the current flight plan = y

The initial time of departure = 4.00pm

Her flight was then delayed for 10 minutes

We are told in the question that:

The current flight plan allows her arrive at her destination three times faster.

This means y= (1/3)x

y = x/3

Hence the equation generated =

y = x/3 +10

y = 1/3(x) + 10

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see the attached figure to better understand the problem

we know that

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in this problem

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Substitute the values in the formula above

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The volume of the nose cone is 45\pi \ ft^{3}

7 0
1 year ago
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Maria is making paper flowers as decorations for the fall dance. She has made 40 flowers so far, and she is 16% finished. If she
alexandr1967 [171]

Answer:

the number of additional she needed is 135

Step-by-step explanation:

The computation is shown below:

GIven that

40 flowers of 16%

So for 100% it would be

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Now she needs to make is

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= 54%

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Hence, the number of additional she needed is 135

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1 year ago
Una fabrica produce 132 litros de yogurt diarios .Con 49 litros se llenan botellas de 0,25litros xada una y con el resto que que
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Answer:

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Step-by-step explanation:

(This exercise has been presented in Spanish and for that reason explanation will be held in Spanish)

La cantidad de botellas de 0,25 litros que se llenan con 49 litros de yogurt es:

x = \frac{49\,L}{0.25\,\frac{L}{botella} }

x = 196\,botellas

La cantidad remanente de yogurt es:

V_{r} = 132\,litros - 49\,litros

V_{r} = 83\,litros

Ahora, la cantidad de botellas de 0,5 litros que se llenan con el volumen remanente es:

y = \frac{83\,litros}{0.5\,\frac{litros}{botella} }

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1 year ago
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MariettaO [177]

Answer:

210.6 cm

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Given that a piece of ribbon is cut into two shorter pieces in the ratio 2.8:1.25.

So that means length of the first smaller piece = 2.8x

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Then difference between their lengths = 2.8x-1.25x = 1.55x

Given that difference is equal to 80.6 centimeters then we get

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then length of the original piece = 2.8x+1.25x

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= 145.6+65

= 210.6 cm

6 0
1 year ago
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