Answer:
(x+2)
Step-by-step explanation:
factor out the equation and get
(x+2)(6x-5)
Answer:
38%
Step-by-step explanation:
Option: 38%.
Total number of numbers: 150
Number of odd numbers: 72
Number of nines: 15
Number of odd numbers other than nine: 72 - 15 = 57
Probability = [number of odd numbers other than nine] / [total number of numbers] = 57/150 = 0.38
0.38 = 38%
Complete question:
Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?
Answer:
Here,
Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)
We are also told only 10 participants are available.
All 10 participants are being exposed to all five levels of the color variable in the same order.
Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.
Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.
But using counterbalancing technique, Dr. Lyte can avoid such an error.
Answer:
Step-by-step explanation:
We need to find the equation of parabola using given information
- Vertex: (0,0)
- Open to the left
- Focal width = 12
If parabola open left and passes through origin then equation is
Focal width = 12
Focal width passes through focus and focus is mid point of focal width.
Focus of above parabola would be (-a,0)
Passing point on parabola (-a,6) and (-a,-6)
Now we put passing point into equation and solve for a
a can't be negative.
Therefore, a=3
Focus: (-3,0)
Equation of parabola:
Please see the attachment of parabola.
