The area of the base of a cylinder is found by dividing the volume of the cylinder by its height. If the volume of the cylinder
2 answers:
<h2><u>Answer:</u></h2>
The Volume of a cylinder is calculated by the following formula (equation 1):
(1)
Where is the radius of the circle that is the base of the cylinder and
the height.
If we divide equation (1) by we obtain the area of the circle, as shown in equation (2):
(2)
Now, we know the volume of the cylinder in this problem is expressed as:
(3)
And its height as:
(4)
Knowing this, let’s find the area of the base (area of a circle):
If we divide each term by the common denominator we have:
Simplifying we finally have:
>>>>> This is the expression of the area of the base
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The given complex number is
z = 1 + cos(2θ) + i sin(2θ), for -1/2π < θ < 1/2π
Part (i)
Let V = the modulus of z.
Then
V² = [1 + cos(2θ)]² + sin²(2θ)
= 1 + 2 cos(2θ) + cos²2θ + sin²2θ
Because sin²x + cos²x = 1, therefore
V² = 2(1 + cos2θ)
Because cos(2x) = 2 cos²x - 1, therefore
V² = 2(1 + 2cos²θ - 1) = 4 cos²θ
Because -1/2π < θ < 1/2π,
V = 2 cosθ PROVEN
Part ii.
1/z = 1/[1 + cos2θ + i sin 2θ]
The denominator is
Therefore
The real part of 1/ = 1/ (constant).
z = 1 + cos(2θ) + i sin(2θ), for -1/2π < θ < 1/2π
Part (i)
Let V = the modulus of z.
Then
V² = [1 + cos(2θ)]² + sin²(2θ)
= 1 + 2 cos(2θ) + cos²2θ + sin²2θ
Because sin²x + cos²x = 1, therefore
V² = 2(1 + cos2θ)
Because cos(2x) = 2 cos²x - 1, therefore
V² = 2(1 + 2cos²θ - 1) = 4 cos²θ
Because -1/2π < θ < 1/2π,
V = 2 cosθ PROVEN
Part ii.
1/z = 1/[1 + cos2θ + i sin 2θ]
The denominator is
Therefore
The real part of 1/ = 1/ (constant).