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Naddika [18.5K]
2 years ago
8

A(n) _____ is a statement whose proof can be deduced directly from a previous theorem. auxiliary line remote interior angle coro

llary triangle 5) A triangle in which one of its interior angles is an obtuse angle is a(n) _____ triangle. equiangular right obtuse acute 6) A triangle with at least two congruent sides is a(n) _____ triangle. right auxiliary isosceles equiangular
Mathematics
1 answer:
bekas [8.4K]2 years ago
8 0

Answer:

The words in order are:

  • corollary
  • obtuse
  • isosceles

Step-by-step explanation:

A corollary is a quick conclusion of a theorem. The proof of a corollary is rather short, compared to the proofs of theorems and other propositions. For example, if you consider the theorem "the area of a circle of radius r is πr²" then an inmediate corollary is "the area of a semicircle of radius r is πr²/2".

Triangles can be classified according to their interior angles. The three types of triangles are acute, right and obtuse. Obtuse triangles are those that have an inner obtuse (>90°) angle. Right triangles have an inner right (=90°) angle, and acute triangles have 3 acute (<90°) inner angles.

Similarly, triangles can be classified according to their sides, as equilateral, isosceles and scalene. Equilateral triangles have all their 3 congruent sides, isosceles triangles have at least 2 congruent sides, and scalene triangles have no congruent sides.

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2 years ago
What is the binomial expansion of (x + 2)4? x4 + 4x3 + 6x2 + 4x + 1 8x3 + 24x2 + 32x x4 + 8x3 + 24x2 + 32x + 16 2x4 + 8x3 + 12x2
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<u>Answer-</u>

\boxed{\boxed{(x+2)^4=x^4+8x^3+24x^2+32x+16}}

<u>Solution-</u>

Given expression is (x+2)^4

Applying Binomial Theorem

\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

Here,

a = x, b = 2 and n = 4

So,

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Expanding the summation

=\dfrac{4!}{0!\left(4-0\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(4-1\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(4-2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(4-3\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(4-4\right)!}x^0\cdot \:2^4

=\dfrac{4!}{0!\left(4\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(3\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(1\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(0\right)!}x^0\cdot \:2^4

=1\cdot x^4\cdot \:1+4\cdot x^3\cdot \:2+6x^2\cdot \:4+4\cdot x\cdot \:8+1\cdot 1\cdot \:16

=x^4+8x^3+24x^2+32x+16

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