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Kisachek [45]
2 years ago
10

What is the length of leg s of the triangle below?

Mathematics
1 answer:
allochka39001 [22]2 years ago
5 0

Answer:

F

Step-by-step explanation:

s²+s²=(4√2)²

2s²=32

s²=16

s=4

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The NEC permits 20% of the cross sectional area in a wireway to be occupied by conductors.for an 8"×8"×6' long wireway the condu
Zanzabum

Answer:

Step-by-step explanation:

Sjaoa

8 0
2 years ago
The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.1 in/s. At
kow [346]

Given:

\dfrac{dr}{dt}=1.4\text{ in/s}

\dfrac{dh}{dt}=-2.1\text{ in/s}

To find:

The rate of change in volume at r=120\text{ in. and }175\text{ in.}

Solution:

We know that, volume of a cone is

V=\dfrac{1}{3}\pi r^2h

Differentiate with respect to t.

\dfrac{dV}{dt}=\dfrac{1}{3}\pi\times \left[(r^2\dfrac{dh}{dt}) + h(2r\dfrac{dr}{dt})\right]

Substitute the given values.

\dfrac{dV}{dt}=\dfrac{1}{3}\times \dfrac{22}{7}\times \left[(120)^2(-2.1) +175(2)(120)(1.4)\right]

\dfrac{dV}{dt}=\dfrac{22}{21}\times \left[-30240+58800\right]

\dfrac{dV}{dt}=\dfrac{22}{21}\times 28560

\dfrac{dV}{dt}=29920

Therefore, the volume of decreased by 29920 cubic inches per second.

6 0
2 years ago
Lupe's dog is 10 inches taller than Sarah's dog.The. Variable s stands for the height of Sarah's dog.Whixh expression stands for
emmainna [20.7K]
The answer is C) s+10 because Lupe's dog is 10 inches taller than Sarah's dog; therefore, all you have to do is add 10 inches to the height of Sarah's dog.
8 0
2 years ago
L = loudness, in decibels (dB); I = sound intensity, in watts/m2; I0 = 10−12 watts/m2
irina [24]
The sound intensity of the Pile Driver is 39.5
 or nearly 40 times the sound intensity of the jackhammer.


Given with Loudness in dB for pile driver = 112 dB
We have to convert it in terms of sound intensity.
First,
112dB/10 = 11.2 

Then we'll use this as exponent of 10
(10)^(11.2) = 1.5849 * 10 ^ 11

Then use the equation of Watts per square meter to find the intensity:
I / (10^-12 W/m^2) =1.5849 * 10 ^ 11
I = sound intensity = 0.158

Then compare:

Sound intensity of Pile Driver/ Sound intensity of Jackhammer
(0.158) / (0.004)
= 39.5
or nearly 40 times the jackhammer.
3 0
2 years ago
Read 2 more answers
The graphs shown are of the form y = ax2. Which graph has the smallest value for a?
Talja [164]
y= x^{2} is a parabola (looks like the letter U).

The letter a represents the coefficient of x^{2} and it controls two things (1) how wide or narrow the parabola is and (2) whether it is concave up (like a U) or concave down (like an up-side-down).

The absolute value of a (the number without the sign) controls how wide or narrow it is. If the absolute value is a fraction less than 1 the graph gets wider. The smaller the absolute value of the fraction the wider the graph gets.

If the absolute value of a is greater than 1 the graph gets narrower (it gets skinnier). The bigger the absolute value the narrower the graph.

So, if all the graphs look like a U (concave up) then the one with the smallest a is the one that is the widest.

The a also controls whether the graph is concave up or concave down. If a is negative

If a is negative the graph is concave down so any graph that is concave down has a smaller value of a than any graph that is concave up. However, if the graph is concave down the one with the smallest a would be the most narrow one.

So to find the one with the smallest a...
If they are all concave up (like a U) pick the widest one
and
If they are not all concave up pick the narrowest one that is concave down (looks like an upside down U)
3 0
2 years ago
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