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alexandr1967 [171]
2 years ago
8

Find the range of y=3/2cos4x-1

Mathematics
1 answer:
MrRissso [65]2 years ago
5 0

Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1,  y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1,  y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

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) We throw 9 identical balls into 7 bins. How many different ways are there to distribute these 9 balls among the 7 bins such th
ArbitrLikvidat [17]

Answer:

28 ways

Step-by-step explanation:

After placing 1 ball in each of the seven bins, there are two balls left.

If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).

If we place each of the remaining balls in a different bin, the number of ways to place the balls is:

n_2=\frac{7!}{(7-2)!2!}=7*3=21

The total number of ways to distribute those balls is 21 + 7 = 28 ways.

3 0
2 years ago
What value of x would make KM ∥ JN?
stepan [7]

Answer:

x = 10

Step-by-step explanation:

By the converse of the side-splitter theorem, if \dfrac{JK}{KL}= \dfrac{NM}{ML} , then KM ∥ JN.

Substitute the expressions into the proportion:

\dfrac{x-5}{x}= \dfrac{x-3}{x+4}

Cross-multiply:

(x – 5)(x+4) = x(x – 3).

Distribute:

x(x) + x(4) - 5(x) - 5(4) = x(x) + x(-3).

Multiply and simplify:

x^2 +4x- 5x - 20 = x^2-3x\\-x-20=-3x\\$Collect like terms$\\-x+3x=20\\2x=20\\$Divide both sides by 2\\x=10

Solve for x: x = 10

Therefore, the value of x that would make KM parallel to JN is 10.

4 0
2 years ago
The temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by th
Soloha48 [4]

It is given in the question that

The temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the equation

K = C + 273.15

To solve for C, we need to get rid of 273.15 and for that we do subtraction, that is

C = K -273.15

Correct option is the first option .

6 0
2 years ago
Read 2 more answers
Marcus pours 12 ounces of cranberry juice into a punch bowl. He uses a container to add sprakling water to the bowl one ounce at
melomori [17]

Answer: There is 20 ounces of liquid in the bowl after adding 8 containers of sparkling water.

Step-by-step explanation:

Since we have given that

Number of ounces of cranberry juice into a punch bowl = 12 ounces

According to question, he uses a container to add sparkling water to the bowl one ounce at a time.

Let the amount of sparkling water added to the bowl be 'x'

Let the total number of ounces of liquid Marcus will have be 'y'.

So, our equation becomes,

y=12+x

Here, we have asked after adding 8 containers of sparkling water .

So, now, our equation becomes,

y=12+x\\\\y=12+8\\\\y=20\ ounces

Hence, there is 20 ounces of liquid in the bowl after adding 8 containers of sparkling water.

6 0
1 year ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
2 years ago
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