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kotegsom [21]
2 years ago
9

What value of x would make KM ∥ JN?

Mathematics
1 answer:
stepan [7]2 years ago
4 0

Answer:

x = 10

Step-by-step explanation:

By the converse of the side-splitter theorem, if \dfrac{JK}{KL}= \dfrac{NM}{ML} , then KM ∥ JN.

Substitute the expressions into the proportion:

\dfrac{x-5}{x}= \dfrac{x-3}{x+4}

Cross-multiply:

(x – 5)(x+4) = x(x – 3).

Distribute:

x(x) + x(4) - 5(x) - 5(4) = x(x) + x(-3).

Multiply and simplify:

x^2 +4x- 5x - 20 = x^2-3x\\-x-20=-3x\\$Collect like terms$\\-x+3x=20\\2x=20\\$Divide both sides by 2\\x=10

Solve for x: x = 10

Therefore, the value of x that would make KM parallel to JN is 10.

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