<u>Given</u>:
An Exhibitor is selling decorative wreaths at an arts and craft show.
The net profit P in dollars from the sales of the Wreaths is given by , where N is the number of wreaths sold.
We need to determine the number of wreaths sold to earn a net profit of $100.
<u>Number of wreaths sold:</u>
The number of wreaths sold to earn a profit of $100 can be determined by substituting P(n) = 100 in the equation , we get;
Thus, the number of wreaths sold is 200.
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :
Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...
The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
The probability that among ten students in a class, at least two of them share a birthday is 0.002.