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2 years ago

Match the x-coordinates with their corresponding pairs of y-coordinates on the unit circle.

1 answer:

5 0

<span>y=+- square root 5 over 3

y^2 + x^2 = 1 => x^2 = 1 - y^2 = 1 - 5/9 = 4/9 => x = +/- 2/3

Answer: x = +/- 2/3

y=+- square root 7 over 3

y^2 + x^2 = 1 => x^2 = 1 - y^2 = 1 - 7/9 = 2/9 => x = +/- (√2) / 3

Answer: x = +/-(√2)/3

y=+- 3 over 3

x^2 = 1 - y^2 = 1 - 3/9 = 1 - 1/3 = 2/3 => x = +/-(√2/3)

Answer: x = +/-√(2/3)

y=+- 2 square root 2 over 2

= y = +/- 2(√2) /2 = √2 ...... these y-coordinates are out of the unit circle, then there is not a corresponding x - coordinate for them.

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Determine and state the vertex of f(x) = x2– 2x – 8 using the method of completing the square.

timurjin [86]

Answer:x²-2x-8

X²-2x=8

X²= -2x + (-1)² = 8 + (-1)²

X²= -2x + 1 = 8 + 1

X²= -2x + 1 = 9

(X-1)² = 9

√(x-1)² = √9

X-1 = ± 3

X= 1 + 3= 4

X= 1 - 3= -2

X= 4 or X= -2

Step-by-step explanation:

3 0

2 years ago

It takes Evan 6 3/4 hours to mow 3 lawns. it takes him 2 1/3 hours to mow Mr. Smiths yard and 1 3/4 hours to mow Ms. Lee's yard.

Ratling [72]

Answer: $2\frac{2}{3}\ hours$

Step-by-step explanation:

Given: The total time taken by Evan to mow the 3 lawns = $6\frac{3}{4}=\frac{27}{4}\ \text{hours}$

Time taken by Evan to mow the first lawn = $2\frac{1}{3}=\frac{7}{3}\ \text{hours}$

Time taken by Evan to mow the second lawn = $1\frac{3}{4}=\frac{7}{4}\ \text{hours}$

Now,Time taken by Evan to mow the third lawn = $\frac{27}{4}-\frac{7}{3}-\frac{7}{4}$

⇒Time taken by Evan to mow the third lawn = $\frac{81-28-21}{12}$

⇒Time taken by Evan to mow the third lawn = $\frac{32}{12}=\frac{8}{3}=2\frac{2}{3}\ hours$

Hence, the time taken by Evan to mow the third lawn = $2\frac{2}{3}\ hours$

7 0

2 years ago

Susan and Daphne are participating in a walk-a-thon at the local community college track to raise money. Susan can walk around t

larisa [96]

All you have to do here is find the lcm.
the time it will take them too complete the lap at the same time is 12 minutes.

6 0

2 years ago

Read 2 more answers

Members of the pep club were selling raffle tickets for $1.50 and $5. The number of $1.50 tickets sold was two less than four ti

marysya [2.9K]

Answer:

see below

Step-by-step explanation:

1.5x + 5y = 1152

x = 4y – 2

We can substitute the second equation into the first equation

Which one-variable linear equation can be formed using the substitution method?

1.5(4y-2) +5y = 1152

Distribute

6y -3 +5y = 1152

Combine like terms

11y-3 = 1152

Add 3 to each side

11y-3+3 = 1152+3

11y = 1155

Divide each side by 11

11y/11 = 1155/11

y = 105

How many $5 raffle tickets were sold?

105 5 dollar tickets were sold

Now we need to find the number of 1.50 tickets

Which equation can be used to determine how many $1.50 raffle tickets were sold?

x = 4y – 2

x = 4(105) -2

=420-2

= 418

How many $1.50 raffle tickets were sold?

418 $1.50 tickets were sold

3 0

2 years ago

Read 2 more answers

The foundation of a building is in the shape of a rectangle, with a length of 20 meters (m) and a width of 18 m. To the nearest

wariber [46]

Answer:

27m

Step-by-step explanation:

It's the Pythagorean Theorem.

20^2+18^2=c^2

400+324=c^2

724=c^2

take the square root of both sides

26.9m=c

to the nearest meter = 27

4 0

2 years ago