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Leviafan [203]
1 year ago
7

Write an arithmetic expression that calculates the yearly interest earned on a amount that's stored in a decimal variable named

principalAmount at an interest rate that's stored in a decimal variable named interestRate. (The interest rate is stored as a decimal fraction like .055 for a rate of 5.5%.)
Mathematics
2 answers:
zalisa [80]1 year ago
7 0

Answer:

yearlyInterest = principalAmount * interestRate * year

Step-by-step explanation:

The general formula for interest is given as:

(principal * rate * time)/100

but in this case the rate has been converted to decimal and the time is in year.

The principal is represented as principalAmount

The rate is represented as interestRate

The time is represented as year

So, the arithmetic expression is to multiply every term together without dividing by 100 since rate is expressed as a decimal fraction.

drek231 [11]1 year ago
5 0

Answer:

Principal Amount x Interest Rate

Step-by-step explanation:

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Examine the steps used to solve the equation.
Elina [12.6K]

Answer:

see below

Step-by-step explanation:

12.5x − 10.2 = 3(2.5x + 4.2) - 6  

Use the distributive property to distribute the 3

12.5x − 10.2 = 7.5x + 12.6 − 6  

Combine like terms

12.5x − 10.2 = 7.5x + 6.6  

Add 10.2 to each side of the equation by using the addition property of equality

12.5x = 7.5x + 16.8

Subtraction 7.5x from each side of the equation by using the subtraction property of equality

5x = 16.8  

Divide by 5 on each side by using the division property of equality

x = 3.36

6 0
2 years ago
Read 2 more answers
Tesla wanted to determine the average miles per kWh that their vehicles get across all models and variations. They took a sample
LiRa [457]

Answer:

\mu_{\bar x} = \mu = E(X) =30KWh

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we select a sample of n =100

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

So then the sample mean would be:

\mu_{\bar x} = \mu = E(X) =30KWh

And the standard deviation would be:

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

6 0
1 year ago
A quality control engineer tests the quality of produced computers. suppose that 5% of computers have defects, and defects occur
11111nata11111 [884]
(a) 0.059582148 probability of exactly 3 defective out of 20

 (b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.

  (a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So

 0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)

 = 0.05^3 * 0.95^17 * 20! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)

 = 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)

 = 0.05^3 * 0.95^17 * 20*19*3

 = 0.000125* 0.418120335 * 1140

 = 0.059582148

  (b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.

 The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)

 = 0.05*0.95^3*24/(1!3!)

 = 0.05*0.857375*24/6

 = 0.171475

 
 So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.
3 0
2 years ago
The atmospheric pressure at sea level is 14.7 lb/in2. This pressure is reduced by half for each 3.6 miles above sea level. Which
Korvikt [17]

<u>Solution-</u>

The atmospheric pressure at sea level = 14.7 lb/in²

Pressure gets reduced by half for each 3.6 miles we move up.

Taking,

x = miles above the sea-level

y = pressure in lb/in²

0         14.7

3.6         7.35

7.2         3.675

10.8         1.8375

It can be observed that both the variables are in inverse proportion as the distance from sea-level increase the pressure decreases.

As only the second graph satisfies the points and inverse proportional condition, so that is the correct graph.

By plotting the graph in excel taking these data set, the following plot was obtained.

8 0
2 years ago
Read 2 more answers
You and a classmate have a bug collection for science class. You find 5 out of every 9 bugs in the collection. You find 4 more bug
FrozenT [24]

Answer:

The total number of bugs in the collection is 36

Step-by-step explanation:

Let

x -----> the number of bugs that you find out

y ----> the number of bugs that the classmate find out

we know that

\frac{x}{y+x} =\frac{5}{9}  -----> equation A

x=y+4 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (20,16)

The total number of bugs in the collection is

(20+16)=36\ bugs

5 0
1 year ago
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