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Artyom0805 [142]
3 years ago
7

A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be

, to the nearest cent, after 6 years?
Mathematics
1 answer:
Andrei [34K]3 years ago
3 0

Answer:

\$6,082.70  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$15,300\\r=14.25\%=0.1425\\x=6\ years

substitute in the formula

V=15,300(1-0.1425)^{6}  

V=15,300(0.8575)^{6}  

V=\$6,082.70  

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dezoksy [38]

Answer:

a). Cost of 44 pupils = $14265

b). Least number of pupils = 31

Step-by-step explanation:

The given question is incomplete; here is the complete question.

The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.

(a) Find the cost when there are 44 pupils.

(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?

Let the equation representing the total cost of maintaining a school is,

C = ax + b

Where C = Total cost of maintaining a school

a = Fee per pupil

b = Fixed running cost

x = number of pupils

a). Cost of 50 pupils = $15705

    Equation will be,

    15705 = 50a + b -------(1)

    Cost of 40 pupils = $13305

    Equation will be,

    13305 = 40a + b --------(2)

    By subtracting equation (2) from equation (1),

    15705 - 13305 = (50a + b) - (40a + b)

    2400 = 10a

    a = 240

    From equation (1),

    b = 3705

    Equation representing the total cost will be,

    C = 240x + 3705

    If x = 44

    C = 240(44) + 3705

    C = $14265

b). If the fee per pupil 'a' = $360

    Let the number of pupils = p

    Total fee of 'p' pupils = $360p

    Total cost to run the school will be = 3705 + 240p

    For the school not to be in the loss,

    360p ≥ 3705 + 240p

    360p - 240p ≥ 3705

    120p ≥ 3705

    p ≥ \frac{3705}{120}

    p ≥ 30.875

    Therefore, to run the school without loss, number pupils should be at least 31.

3 0
2 years ago
In 2012, on average, about $9.46\times10^{-1}$ pound of potatoes was produced for every $2.3\times10^{-5}$ acre harvested. How m
muminat

Answer:

4.113 × 10⁴ pounds per acre = 41,130 pounds per acre to the nearest pounds per acre

Step-by-step explanation:

9.46 × 10⁻¹ pounds of potatoes were produced for every 2.3 × 10⁻⁵ acre harvested. The average pounds of potatoes harvested per acre would be pounds of potatoes/acres harvested =  9.46 × 10⁻¹ pounds/2.3 × 10⁻⁵ acre = 4.113 × 10 ⁻¹⁻⁻⁵ = 4.113 × 10⁵⁻¹ = 4.113 × 10⁴ pounds per acre = 41,130 pounds per acre to the nearest pounds per acre.

6 0
2 years ago
Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.
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Answer:  The required inequality is x+\dfrac{1}{4}x+\dfrac{3}{2}x>22. and its solution is x>8.

Step-by-step explanation:  Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written \frac{1}{4} as many articles as Mustafa has and Gia has written \frac{3}{2} as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper.  Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.

And the solution of the above inequality is as follows :

x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.

Thus, the required inequality is x+\dfrac{1}{4}x+\dfrac{3}{2}x>22. and its solution is x>8.

4 0
2 years ago
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Nadine is going to paint her younger sister’s toy chest, including the bottom. What is the approximate surface area she will pai
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Answer:

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2HW=2(19*19)=722

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2 years ago
Sofia is working two summer jobs, making $12 per hour babysitting and making $8 per hour clearing tables. In a given week, she c
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The possible values for the number of whole hours clearing tables that she must work to meet her requirements is 2, 3 hours

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Amount earned in clearing tables = $ 8 per hour

In a given week, she can work a maximum of 17 total hours and must earn a minimum of $180

Sofia worked 14 hours babysitting

Therefore,

Amount earned at babysitting = 14 x 12 = 168

Thus, Sofia earned $ 168 at babysitting

Sofia must earn a minimum of $ 180

Remaining amount to be earned = 180 - 168 = 12

Thus, Sofia must earn $ 12 from clearing tables

Amount earned in clearing tables = $ 8 per hour

So, she must work for atleast 1.5 hours to get $ 12 from clearing tables

She can work a maximum of 17 total hours and Sofia worked 14 hours babysitting

Remaining is 17 - 14 = 3 hours

Thus possible values for the number of whole hours clearing tables that she must work to meet her requirements is 2 hours or 3 hours

3 0
2 years ago
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