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Artyom0805 [142]
2 years ago
7

A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be

, to the nearest cent, after 6 years?
Mathematics
1 answer:
Andrei [34K]2 years ago
3 0

Answer:

\$6,082.70  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$15,300\\r=14.25\%=0.1425\\x=6\ years

substitute in the formula

V=15,300(1-0.1425)^{6}  

V=15,300(0.8575)^{6}  

V=\$6,082.70  

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Answer:

4x\sqrt{26}.

Step-by-step explanation:

Given information:

Leg_1=4x

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According to the Pythagoras theorem,

(hypotenuse)^2=(Leg_1)^2+(leg_2)^2

Using Pythagoras theorem, we get

(hypotenuse)^2=(4x)^2+(20x)^2

(hypotenuse)^2=16x^2+400x^2

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Taking square root on both sides.

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We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

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Volume of each candle will be equal to volume of sphere.

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We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

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\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}

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